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Mice21 [21]
3 years ago
10

find the perimeter (p) of a rectangle with a length (1) of 12m and a width (w) of 8.4m using the formula p=21+2w

Mathematics
1 answer:
NikAS [45]3 years ago
4 0

Answer:

The answer is 40.8 m.

Step-by-step explanation:

To find the perimeter of the rectangle, use the formula P= 2(l)+ 2(w). Plug in the information given in the question, and the equation will look like

P= 2(12m) + 2(8.4m)

Solve the equation, and the final answer will be 40.8 m.

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hope this helps.

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Is 56 a multiple of 6?
lbvjy [14]
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3 years ago
Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
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emmainna [20.7K]

Answer:

-4/5 or -0.8

Step-by-step explanation:

Slope: (y2 - y1)/(x2 - x1)

m = (49 - 45)/(5 - 10)

= 4/-5

= -⅘

4 0
3 years ago
What is 5/7 of a 100 give your answer correct to the nearest whole number
Sati [7]

Answer:

71.4 I think this is it my dad helped

7 0
3 years ago
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