<span>6^1/3 * 6^1/4 = 6^x/y
The key to solving this problem is understanding properties of exponents:
If you are multiplying two powers with the same base (in this case the base is 6), the result is the base raised to the power of the two exponents added together.
6^1/3+1/4 = 6^x/y
6^7/12 = 6^x/y
So the product would be 6^7/12
x = 7
y = 12</span>
log(3x) = log(2x-4)
taking antilog of both sides:
3x = 2x - 4
3x - 2x = -4 [subtracting 2x from both sides]
x = -4
and we're done already!
Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are

The volume of the box is equal to


so

simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A

solve for y

Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x

therefore
The original length was 41 inches and the original width was 16 inches
Its c I've done this before
Answer:
Step-by-step explanation:
1) 5
2) -3, which becomes 3
3) it would land at either 3, or -3
4) 7 or -7
5) if it is to the left, that means it is negative. there fore, your answer is -4