All categories

3 years ago

Find the probability of getting heads 2 times in a row, then rolling a 6 sided die and getting

Mathematics

1 answer:

Sliva [168]3 years ago

4 0

Answer:

1/12

Step-by-step explanation:

The probability of rolling a die and landing it on heads is 1/2 percent. Flipping the coin another time and landing it on heads is 1/4 percent because you need to multiply when doing probabilities, so 1/2 times 1/2 equals 1/4.

Now moving on, rolling a 6 sided die and getting either a 1 or 6 is 1/3 percent because 1 and 6 are two different numbers you can roll so it's 2/6, and when it's simplified, it's 1/3.

After doing that, to find the probability of the whole equation, you would need to multiply 1/4 times 1/3 which would give you 1/12 as your answer.

You might be interested in

Plz help I’m timed :(

Murrr4er [49]

Answer:

y=5/3x+5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which is the best approximate solution of the system of linear equations y = 1.5x – 1 and y = 1?

vazorg [7]

I think the answer is B.(1.33,1)
but i'm not sure..

3 0

3 years ago

Read 2 more answers

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

4 years ago

GUYS PLEASE ANSWER! I'M DESPERATE! WILL MARK BRAINLIEST

uysha [10]

A. Graph B because the slope is at a constant rate
B. Graph A because since it is slowly opened the rise of the slope starts of small then rises more
C. Graph C since it’s opened a lot the beginning and closed at the end so the rise would start high then go lower as time goes by

8 0

4 years ago

Read 2 more answers

Which set of values makes the inequality n≥-5 true

vladimir1956 [14]

Answer:

n has to be greater than or equal to -5.

The numbers -5,-4,-3,-2,-1,0,1....... work for that inequality

Step-by-step explanation:

5 0

4 years ago