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riadik2000 [5.3K]
3 years ago
11

If the cost of the framing material is $ 13 13 per linear foot and the cost of the pane glass is $ 24 24 per square foot, what i

s the total cost of a window with a base length of 4 4 feet?
Mathematics
1 answer:
miskamm [114]3 years ago
5 0
I thank you should time 1313*2424==318.27
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The question is in the picture
kompoz [17]

Answer:

questions 2 answe is x+3less than equal to 13

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3 years ago
If sin θ = cos 40°, 0<θ<90°, what is θ?
Bezzdna [24]

Answer:

θ =  50 degrees

Step-by-step explanation:

we have  sin θ = cos 40°

 θ = arcsin ( cos 40°)

and make sure θ is less than 90  and greater than 0

 θ = arcsin (0.766044443)

θ =  50 degrees

3 0
3 years ago
36 3⁄4 gallons of water come out of a hose in 15 minutes. Write the ratio in fractional form and determine the water rate in gal
Brrunno [24]

Answer:

Step-by-step explanation:

If 3⁄4 gallons of water come out of a hose in 15 minutes, to calculate the rate of water that comes out in an hour (60 minutes), we will use the expression;

3/4 gallons = 15 minutes

x gallons = 60minutes

cross multiply

15x = 3/4 * 60

15x = 180/4

15x = 45

x = 45/15

x = 3/1

x = 3:1

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7 0
3 years ago
Anne’s family is driving to her uncle’s house. The family travels 383.5 miles between 10:15 a.m. and 4:45 p.m.Anne tells her fam
Ede4ka [16]

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3 years ago
(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte
Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 27<em>a</em>₃ = 3

<em>f'</em> (2) = <em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 12<em>a</em>₃ = -1

7 0
2 years ago
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