Can you show a picture please?
Answer:
<h2>$357</h2>
Step-by-step explanation:
We have a rectangle measuring 25 feet × 9 feet. Remove from the rectangle two regular hexagons with a side length equal to 2 feet.
The formula of an area of a rectangle:
![A_r=lw](https://tex.z-dn.net/?f=A_r%3Dlw)
l - length, w - width.
Substitute l = 25 ft and w = 9 ft:
![A_r=(25)(9)=225\ ft^2](https://tex.z-dn.net/?f=A_r%3D%2825%29%289%29%3D225%5C%20ft%5E2)
The formula of an area of a regular hexagon:
![A_h=6\cdot\dfrac{a^2\sqrt3}{4}](https://tex.z-dn.net/?f=A_h%3D6%5Ccdot%5Cdfrac%7Ba%5E2%5Csqrt3%7D%7B4%7D)
a - side
Substitute a = 2 ft:
![A_h=6\cdot\dfrac{2^2\sqrt6}{4}=6\sqrt3\ ft^2](https://tex.z-dn.net/?f=A_h%3D6%5Ccdot%5Cdfrac%7B2%5E2%5Csqrt6%7D%7B4%7D%3D6%5Csqrt3%5C%20ft%5E2)
The area of the wall:
![A=A_r-2A_h](https://tex.z-dn.net/?f=A%3DA_r-2A_h)
Substitute:
![A=225-2(6\sqrt3)=225-12\sqrt3\approx225-20.785=204.215\ ft^2](https://tex.z-dn.net/?f=A%3D225-2%286%5Csqrt3%29%3D225-12%5Csqrt3%5Capprox225-20.785%3D204.215%5C%20ft%5E2)
Paiting the wall costs $1.75 per ft². Calculate:
![(\$1.75)(204.215)\approx\$357](https://tex.z-dn.net/?f=%28%5C%241.75%29%28204.215%29%5Capprox%5C%24357)
Answer:
56 deg
Step-by-step explanation:
All internal angles of a triangle add up to 180 degrees
hence,
∠O + ∠R + ∠F = 180
x + (x+43) + (x-31) = 180
x + x+43 + x -31 = 180
3x+ 12 = 180
3x = 180 - 12 = 168
x = 168/3 = 56 deg
Answer:
The limit converges to -1/5
Step-by-step explanation:
Plugging in infinity for n you will see that the limit will go to infinity/infinity so you have to apply L'Hopitals Rule
Doing so you find it will turn into the limit of (4-6)/10 as n goes to infinity. This then simplifies to -1/5
Parallel lines will have the same slope
y - y1 = m(x - x1)
slope(m) = 2
origin (0,0)...x1 = 0 and y1 = 0
now we sub
y - 0 = 2(x - 0) <===