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2 years ago

7

Write a rule to describe each reflection.

1 answer:

Oksanka [162]2 years ago

6 0

Answer: ok so if it is ok im sorry but like how is it like is there supposed to be a number? im sorryyy i thught i had it before i saw the picture

Step-by-step explanation:

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A person sold an article at a profit of 15% if he sold it for Rs 81 less , his loss would have been 12% find the cost price of t

Misha Larkins [42]

Answer:

let cp be x

sp= 115x/100 ---(when 15%gain)

sp = 88x/100------(when 12% loss

according to question

115x/100 - 88x/100 = 81

or, (115x-88x)= 8100

or, 27x = 8100

or, x= 8100/27

x = 300

hence cp is RS 300

3 0

2 years ago

Find the radius of a circle with a circumference of 30 units. Round your answer to the nearest tenth (1 decimal place).

Vlad [161]

Answer:

The radius would be 4.8

Step-by-step explanation:

The circumerfence of a circle can be found use the equation C=2 $\pi$ r. So since we are given the circumerce we need to rearrange the eqaution to it looks like $\frac{30}{2\pi }$ =r. when we do this out we find that the radius equals 4.8.

4 0

3 years ago

I need help does anyone know?

Rzqust [24]

Answer:1 4/5

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Help please with this question?

xxMikexx [17]

$G(x+1)= \sqrt{(x+1)^2+4} \\ G(x+1)= \sqrt{x^2+2x+1+4} \\ G(x+1)= \sqrt{x^2+2x+5}$

7 0

3 years ago

The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

3 years ago