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3 years ago

I'M BEING TIMED!! NEED HELP NOW!! PLEASE!!

Mathematics

2 answers:

Kay [80]3 years ago

7 0

The required equation of line is y=-6x-57.

Step-by-step explanation:

The point slope form of a line is

y-y_1=m(x-x_1)y−y

=m(x−x

)

Where m is slope of the line.

It is given that a line that passes through (–9, –3) and has a slope of –6.

Substitute m=-6, x₁=-9 and y₁=-3 in the above equation.

y-(-3)=-6(x-(-9))y−(−3)=−6(x−(−9))

y+3=-6x-54y+3=−6x−54

Subtract 3 from both the sides.

y=-6x-54-3y=−6x−54−3

y=-6x-57y=−6x−57

Therefore the required equation of line is y=-6x-57.

Schach [20]3 years ago

5 0

Answer:

D).y+3=-6(x+9)

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What is 0.2857142857 rounded to the nearest whole percent? pls help me

Grace [21]

29% would be the answer if you are rounding up

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2 years ago

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nikitadnepr [17]

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3 years ago

What is the greatest factor (GCF) of 24 and 40?

bagirrra123 [75]

Answer:

Step-by-step explanation:

that;'s what i put the first time

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3 years ago

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If <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-2" id="TexFormula1" title="f(x)=x^2-2" alt="f(x)=x^2-2" align="absmiddle"

jek_recluse [69]

Answer:

$\boxed{f(6) = 34}$

Step-by-step explanation:

Composition of functions occurs when we have two functions normally written similar or exactly like f(x) & g(x) - you can have any coefficients to the (x), but the most commonly seen are f(x) and g(x). They are written as either f(g(x)) or (f o g)(x). Because our composition is written as $(f \circ g)(2)$ , we are replacing the x values in the g(x) function with 2 and simplifying the expression.

$g(2) = 3(2)$

$g(2) = 6$

Now, because we are composing the functions, this value we have solved for now replaces the x-values in the f(x) function. So, f(x) becomes f(6), and we use the same manner as above to simplify.

$f(6) = (6)^2-2$

$f(6) = 36-2$

$f(6) = 34$

Therefore, when we compose the functions, our final answer is $\bold{f(6) = 34}$ .

4 0

3 years ago

Read 2 more answers

Find the shaded sector and the length of the arc. Round to the nearest hundredth.

Dovator [93]

Answer:

Step-by-step explanation:

I'll show you how to do the first one; the other are exactly the same, so pay attention.

The formula for arc length is

$AL=\frac{\theta}{360}*2\pi r$ where θ is the central angle's measure. It just so happens that the measure of the central angle is the same as the measure of the arc it intercepts. Our arc shows a measure of 40°; this measure is NOT the same as the length. Measures are in degrees while length is in inches, or cm, or meters, etc. Going off that info, our central angle measures 40°. Filling in the formula and using 3.1415 for π:

$AL=\frac{40}{360}*2(3.1415)(3)$ . I'm going to reduce that fraction a bit (and I'll use the same reduction in the Area of a sector coming up next):

$AL=\frac{1}{9}*2(3.1415)(3)$ which makes

AL = 2.09 units. Now for Area of the Sector. The formula is almost identical, but instead uses the idea that the area of a circle is πr²:

$A_s=\frac{\theta}{360}*\pi r^2$ where θ is, again, the measure of the central angle (which is the same as the measure of the arc it intercepts). Filling in:

$A_s=\frac{1}{9}*(3.1415)(3)^2$ which simplifies a bit to

$A_s=\frac{1}{9}*(3.1415)(9)$ . As you can see, the 9's cancel each other out, leaving you with

$A_s=3.14$ units²

7 0

2 years ago

Read 2 more answers