The required equation of line is y=-6x-57.
Step-by-step explanation:
The point slope form of a line is
y-y_1=m(x-x_1)y−y
1
=m(x−x
1
)
Where m is slope of the line.
It is given that a line that passes through (–9, –3) and has a slope of –6.
Substitute m=-6, x₁=-9 and y₁=-3 in the above equation.
y-(-3)=-6(x-(-9))y−(−3)=−6(x−(−9))
y+3=-6x-54y+3=−6x−54
Subtract 3 from both the sides.
y=-6x-54-3y=−6x−54−3
y=-6x-57y=−6x−57
Therefore the required equation of line is y=-6x-57.
