Question

I'M BEING TIMED!! NEED HELP NOW!! PLEASE!!

Answer 1

The required equation of line is y=-6x-57.

Step-by-step explanation:

The point slope form of a line is

y-y_1=m(x-x_1)y−y

1

=m(x−x

1

)

Where m is slope of the line.

It is given that a line that passes through (–9, –3) and has a slope of –6.

Substitute m=-6, x₁=-9 and y₁=-3 in the above equation.

y-(-3)=-6(x-(-9))y−(−3)=−6(x−(−9))

y+3=-6x-54y+3=−6x−54

Subtract 3 from both the sides.

y=-6x-54-3y=−6x−54−3

y=-6x-57y=−6x−57

Therefore the required equation of line is y=-6x-57.

Answer 2

Answer:

D).y+3=-6(x+9)