We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is
but this would imply that
, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".
Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have
and solving gives
, which makes more sense. Then the number of extra spades in the deck must be 2.
We conclude that the distance between points C and D is 5 units.
<h3>
How to find the distance between the two points?</h3>
Remember that if we have two points (x₁, y₁) and (x₂, y₂), the distance between these points is:
d = √( (x₂ - x₁)^2 + (y₂ - y₁)^2)
In this case, we know that:
Point C has the coordinates (-1, 4)
Point D has the coordinates (2, 0)
Then the distance between these two points is:
d = √( (-1 - 2)^2 + (0 - 4)^2) = √25 = 5
We conclude that the distance between points C and D is 5 units.
If you want to learn more about distance between points:
brainly.com/question/7243416
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Answer
It is 11/12
hope im not late i hope it helps
Step-by-step explanation:
First row, the answer on the left , -5 3/4 - 4 2/3
Answer:
range is between 55.5 to 64.5
Step-by-step explanation:
Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches
68% is 1 standard deviation from mean
To get the range of 1 standard deviation we add and subtract standard deviation from mean
mean = 60
standard deviation = 4.5
60 - 4.5= 55.5
60+4.5 = 64.5
1 standard deviation is between 55.5 to 64.5
That is 68% range is between 55.5 to 64.5
