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Gekata [30.6K]
3 years ago
7

Please help, will give brainliest!!!!

Mathematics
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

A=20, B=60, C=80

Step-by-step explanation:

Supplementary angles are those which add to 180 o. Complementary angles are those which add to 90°

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Please help.ASAP.Thank you!
frosja888 [35]
8.8, you have to find the distance between each dash and see if the two number lines on #11 match.


4 0
3 years ago
Read 2 more answers
Can someone help? Show work
Kamila [148]
Given the isosceles right triangle in which each of its legs has a measure of 4:

Let c = hypotenuse
a = one of the legs of the triangle
b = the other leg of the triangle

Use the Pythagorean Theorem to solve for the measure of the hypotenuse:

c^ 2 = a^2 + b^2

c^ 2 = (4)^2 + (4)^2
c^ 2 = 16 + 16
c^2 = 32

Next, take the square root of each side of the equation to solve for c:

√(c^2) = √(32)

c = 4√(2)

Therefore, the correct answer is Option 3) 4√(2).
8 0
3 years ago
An adult blue whale can eat 4.0 x 10' krill
kotykmax [81]
Ratio=4.0 *10⁷ Krill / day
amount of krill=ratio * days
amount of krill=(4.0*10⁷ Krill /day)(3.65*10² days)=1.46*10¹⁰ krill

Answer: 1.46*10¹⁰ krill
3 0
3 years ago
Involves sine/cosine rules
katen-ka-za [31]

Answer:

44.47 cm² (nearest hundredth)

Step-by-step explanation:

Area of ΔABC = 1/2 x base x height

⇒ 21 = 1/2 x 7 x BC

⇒ BC = 6 cm

Pythagoras' Theorem: a² + b² = c²

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

⇒ AB² + BC² = AC²

⇒ 7² + 6² = AC²

⇒ AC² = 85

⇒ AC = √85 cm

Cosine rule to find length AD:

      c² = a² + b² - 2 ab cosC

⇒ DC² = AD² + AC² - 2(AD)(AC)cos(DAC)

⇒ 9.2² = AD² + (√85)² - 2(AD)(√85)cos 73°

⇒ AD²  - 5.39106...AD + 0.36 = 0

⇒ AD = 5.323442445, 0.06762541414

⇒ AD = 5.323442445

Area of a triangle ADC: (1/2)absinC

(where a and b are adjacent sides and C is the angle between them)

⇒ area = (1/2) × AC × AD × sin(DAC)

⇒ area = (1/2) × √85 × 5.323442445 × sin(73°)

⇒ area =23.4675821... cm²

Area of quadrilateral = area of ΔABC + area of ΔADC

                                   = 21 + 23.4675821...

                                   = 44.47 cm² (nearest hundredth)

4 0
2 years ago
A sample of 66 obese adults was put on a low-carb diet for a year. The average weight loss was 11 pounds and the standard deviat
Illusion [34]

Answer:

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{19}{\sqrt{66}} = 6.02

The lower end of the interval is the sample mean subtracted by M. So it is 11 - 6.02 = 3.98 pounds

The 99% lower confidence bound for the true average weight loss is 3.98 pounds.

This means that we can be 99% sure that the mean weight loss for all obese adults on a low-carb diet is positive.

7 0
3 years ago
Read 2 more answers
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