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3 years ago

The table shows a linear function. Which equation represents the function?

Mathematics

1 answer:

4vir4ik [10]3 years ago

8 0

Question is not complete and so I have attached the complete question.

Answer:

C: f(x) = -½x + 4

Step-by-step explanation:

Using slope formula between 2 points, we know that;

slope; m = (y2 - y1)/(x2 - x1)

Let's consider 2 points from the table;

(0, 4) and (-4, 6)

Thus;

m = (6 - 4)/(-4 - 0)

m = 2/-4

m = -½

Now using slope intercept form equation which is y - y1 = m(x - x1), we can find the equation of the function by picking on point say (0, 4).

Thus;

y - 4 = -½(x - 0)

y - 4 = -½x

y = -½x + 4

Thus;

f(x) = -½x + 4

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The edges of a cube increase at a rate of 2 cm divided by s. How fast is the volume changing when the length of each edge is 40

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

Let the edge of the cube be a .

Given

$\frac{da}{dt} = 2 cm/s$

Volume V = a³

$\frac{dV}{dt} = 3a^ 2\frac{da}{dt}$

= 3a² x 2

= 6a²

If a = 40 cm

$\frac{dV}{dt} = 6 \times 40\times40$

= 9600 cm³/s .

5 0

3 years ago

1: 63 is 75% of what number?

MissTica

1. It is 84.
x=100%
63=75%

(63*100)/75=84

4 0

3 years ago

Read 2 more answers

Let f(x)= x(2x-3)/(x+2)x. Find the domain, vertical and horizontal asymptote

Reptile [31]

Step-by-step explanation:

Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues

Here, we have

$\frac{x(2x - 3)}{(x + 2)x}$

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.

Since, we don't want x to be 0,

We have a removable discontinuity at x=0

Now, we have

$\frac{2x - 3}{x + 2}$

We don't want the denomiator be zero because we can't divide by zero.

$x + 2 = 0$

$x = - 2$

So our domain is

All Real Numbers except-2 and 0.

The vertical asymptors is x=-2.

To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of

The leading coeffixent of the numerator/ the leading coefficent of the denomiator.

So that becomes

$\frac{2}{1} = 2$

So we have a horinzontal asymptofe of 2

7 0

2 years ago

Make a table of values and create a line of best fit

Anni [7]

<h2>Explanation:</h2><h2></h2>

Hello! remember you have to write complete questions in order to get good and exact answers. Here I'll explain this in a general way assuming the following table:

$\begin{array}{cc}x & y\\0 & 0\\1 & 2\\2 & 4\\3 & 6\\4 & 8\\5 & 10\end{array}$

As you can see, x increases in steps of 1 units. So let's check the difference in y:

$\bullet \ \text{From x=0 to x=1} \\ \\ \Delta y=2-0=2 \\ \\ \\ \bullet \ \text{From x=1 to x=2} \\ \\ \Delta y=4-2=2 \\ \\ \\ \bullet \ \text{From x=2 to x=3} \\ \\ \Delta y=6-4=2 \\ \\ \\ \bullet \ \text{From x=3 to x=4} \\ \\ \Delta y=8-6=2 \\ \\ \\ \bullet \ \text{From x=4 to x=5} \\ \\ \Delta y=10-8=2$

So we have a constant difference and we can conclude the table represents a line. Since the line passes through then y is directly proportional to x, so we can write:

$y=kx \\ \\ Where: \\ \\ k \ is \ constant \ of \ proportionality \ or \ the \ slope$