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gavmur [86]
3 years ago
13

Point A is the incenter of ΔDEF. Point A is the incenter of triangle D E F. Lines are drawn from the points of the triangle to p

oint A. Lines are drawn from point A to the sides of the triangle to form right angles and line segments A L, A M, and A N. The length of A L is 5 x minus 1 and the length of A M is 6 x minus 3. What is the length of NA? 2 units 9 units 11 units 14 units
Mathematics
2 answers:
horrorfan [7]3 years ago
5 0

Answer:

B 9 Units

Step-by-step explanation:

Trava [24]3 years ago
4 0

Answer:

9 points

Step-by-step explanation:

took the quiz edge2020

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Is the relationship linear, exponential, or neither
photoshop1234 [79]

Answer: exponential

Step-by-step explanation:

4 0
3 years ago
Jake says adding 0 to an addendum does not change a sum. Is he correct
siniylev [52]
Nothing changes if you don't add anything. 

Example:

10+10=20
20+0=20
 
nothing changes.
5 0
3 years ago
Prove the identity (sin6x)/(1+cos6x)=tan3x.
Vikentia [17]
Use double angle identity
sin(2x) = 2 sin x cos x \\  \\ cos(2x) = 2cos^2 x - 1

We can relate '6x' to '3x' in the same way since 6 is 2*3.
sin(6x) = 2 sin (3x) cos (3x) \\ \\ cos(6x) = 2cos^2 (3x) - 1

Now sub into left side of identity. Simplify until it equals right side.
\frac{2 sin(3x) cos(3x)}{1+(2cos^2 (3x) -1)} = \frac{2 sin(3x) cos(3x)}{2cos^2 (3x) } = \frac{sin(3x)}{cos(3x)} = tan (3x)
3 0
4 years ago
(-3,y), (-9,-2); m=1
12345 [234]

Answer:

The value of y is 4

The equation of line is y = x + 7   .

Step-by-step explanation:

Given as :

The points are

(x_1, y_1) = (- 3, y)

(x_2, y_2) = (- 9, -2)

The slope = m = 1

Now,<u> The slope is calculated in points form</u>

So, Slope = \dfrac{y_2-y_1}{x_2-x_1}

I.e m = \dfrac{y_2-y_1}{x_2-x_1}

or, 1 = \dfrac{- 2 - y}{- 9- (-3)}

or, 1 = \dfrac{- 2 - y}{- 6}

or, 1 × (-6) = - 2 - y

or, - 6 = - 2- y

or, y = - 2 + 6

∴ y = 4

So, The new points as

(x_1, y_1) = (- 3, 4 )

(x_2, y_2) = (- 9, -2)

<u>So, the equation of line in slope - point form can be written as</u>

y - y_1 = m ( x - x_1 )

i.e y - 4 = ( 1 ) × ( x - (-3) )

or, y - 4 = x + 3

∴ y = x + 3 + 4

Or, y = x + 7

So, The equation of line is y = x + 7

Hence The value of y is 4

And The equation of line is y = x + 7   . Answer

8 0
3 years ago
If tan θ =(√3)/3, 0◦&lt; θ &lt; 360◦,
svetlana [45]
Arctan (√3 /3) = 30°. = π/6 rad

That is the value searched, in degrees and radians.

You can verifiy that tan(30°) = sin(30°) / cos(30°) = [1/2] / [√3/2] = 1/√3 = √3 / 3

 
3 0
3 years ago
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