So I will be assuming that EG = 8 is the length
of the line segment EG. If that's the case, therefore the coordinates of G would
simple be:
G =11 ± 8
G = 11 – 8, 11 + 8
G = 3, 19
<span>So G can have a coordinate of 3 or 19.</span>
Answer:
Step-by-step explanation:
5) P1=(x1,y1) P2=(x2,y2)
P1=(0,1) P2=(4,-1)
m = y2-y1 / x2-x1
m= -1-1 / 4-0
m= -1/4
point-slope formula (memorize this ) [y-y1=m(x-x1)
y-1= -1/4(x-0)
y-1 = -1/4x
y= -1/4x+1
6) P1=(-3,3) P2=(0,-1) ( same process as above)
m=-1-3 / 0-(-3)
m= -4/3
y-3= -4/3(x-(-3))
y-3 = -4/3(x+3)
y-3 = -4/3x -4
y = -4/3x -4+3
y = -4/3x -1
7) P1=(0,-1) P2=(-2,-2) (same process as above)
m= -2-(-1) / -2-0
m= -2+1 / -2
m= -1 / -2
m= 1/2
y-(-1) =1/2(x-0)
y+1= 1/2x
y= 1/2x -1
8) P1=(1,-5) P2=(-2,2)
m=
I'll let you work out the rest of 8.. just follow what i've shown above.. ask later if you need more help :)
Answer:
D
Step-by-step explanation:
(-2 1/2, -3) = (-5/2 , -3) & (1, -3)
![Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(1-[\frac{-5}{2}])^{2}+(-3-[-3])^{2}}\\\\ =\sqrt{(1+\frac{5}{2})^{2}+(-3+3)^{2}}\\\\ =\sqrt{(\frac{7}{2})^{2}} \\\\=\frac{7}{2}\\\\=3\frac{1}{2}](https://tex.z-dn.net/?f=Distance%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%281-%5B%5Cfrac%7B-5%7D%7B2%7D%5D%29%5E%7B2%7D%2B%28-3-%5B-3%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%281%2B%5Cfrac%7B5%7D%7B2%7D%29%5E%7B2%7D%2B%28-3%2B3%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%28%5Cfrac%7B7%7D%7B2%7D%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%5Cfrac%7B7%7D%7B2%7D%5C%5C%5C%5C%3D3%5Cfrac%7B1%7D%7B2%7D)
Answer:
The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.
Step-by-step explanation:
