Answer:
27y - 6
Step-by-step explanation:
3(9y - 2) Multiply 3 times each term in the parentheses
3 * 9y = 27y
3 * -2 = -6
Answer:
Slope is -4
Step-by-step explanation:
An algebraic expression to represent the value of this car after M months is y=Mx+C.
We have given that the
The straight-line depreciation equation for a car is,
y = -2,680x + 26,800.
therefore after 4moths
y = -2,680(4) + 26,800.
y = -10720 + 26,800.
y=16080
<h3>
What is the slope?</h3>
The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as rise over run (change in y divided by change in x)
b. For find after the 75 months replace x by 75 and slolve the given inequality.
Suppose that M represents the length of time in months when
the car still has value.
An algebraic expression to represent the value of this car after M months.
y=Mx+C.
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Answer:
x= -12
Step-by-step explanation:
move variable to left and change its sign
= 4x - 20 = -68
move constant to the right and change its sign
= 4x = -68 + 20
calucate the sum
= 4x = -48
divide both sides of the equation by 4
x= -12
Answer:
The number of students we expect to have an interval that does not contain the true mean value is,
.
Step-by-step explanation:
A [100(1 - α)%] confidence interval for true parameter implies that if 100 confidence intervals are created then [100(1 - α)] of these 100 confidence intervals will consist the true population parameter value.
Here α is the significance level. It is defined as the probability rejecting the claim that the true parameter value is not included in the 100(1 - α)% confidence interval.
It is provided that 255 students create the same confidence interval, correctly.
Then the number of students we expect to have an interval that does not contain the true mean value is, ![255\times [\alpha\%]](https://tex.z-dn.net/?f=255%5Ctimes%20%5B%5Calpha%5C%25%5D)
For instance, if the students are creating a 95% confidence interval for mean then the number of students we expect to have an interval that does not contain the true mean will be:
The significance level is:

Number of students we expect to have an interval that does not contain the true mean will be: ![255\times [\alpha\%]=255\times 0.05=12.75\approx13](https://tex.z-dn.net/?f=255%5Ctimes%20%5B%5Calpha%5C%25%5D%3D255%5Ctimes%200.05%3D12.75%5Capprox13)
Thus, 13 of the 255 confidence intervals will not consist the true mean value.