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beks73 [17]
3 years ago
12

Ab has endpoints A(4,5) and B(0,-2). What will be the after rotation

Mathematics
1 answer:
spin [16.1K]3 years ago
4 0

Answer:

here are formulas you havent clearly said how much degrees

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Simplify 3(9y - 2) WILL GIVE BRAINLIST IF FULLY EXAMPLED HELP!
Musya8 [376]

Answer:

27y - 6

Step-by-step explanation:

3(9y - 2)   Multiply 3 times each term in the parentheses

3 * 9y = 27y

3 * -2 = -6

5 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (-10, -8) and
galina1969 [7]

Answer:

Slope is -4

Step-by-step explanation:

7 0
3 years ago
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8. The straight line depreciation equation for a car is
kifflom [539]

An algebraic expression to represent the value of this car after M months is y=Mx+C.

We have given that the

The straight-line depreciation equation for a car is,

y = -2,680x + 26,800.

therefore after 4moths

y = -2,680(4) + 26,800.

y = -10720 + 26,800.

y=16080

<h3>What is the slope?</h3>

The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as rise over run (change in y divided by change in x)

b. For find after the 75 months replace x by 75 and slolve the given inequality.

Suppose that M represents the length of time in months when

the car still has value.

An algebraic expression to represent the value of this car after M months.

y=Mx+C.

To learn more about the line visit:

brainly.com/question/1821791

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5 0
2 years ago
-20 = -4x – 68 please solve it
Jet001 [13]

Answer:

x= -12

Step-by-step explanation:

move variable to left and change its sign

= 4x - 20 = -68

move constant to the right and change its sign

= 4x = -68 + 20

calucate the sum

= 4x = -48

divide both sides of the equation by 4

x= -12

7 0
4 years ago
There are 255 students this term completing this same assignment. Assuming they calculated the CI correctly, how many students s
andrey2020 [161]

Answer:

The number of students we expect to have an interval that does not contain the true mean value is,  255\times [\alpha\%].

Step-by-step explanation:

A [100(1 - α)%] confidence interval for true parameter implies that if 100 confidence intervals are created then [100(1 - α)] of these 100 confidence intervals will consist the true population parameter value.

Here α is the significance level. It is defined as the probability rejecting the claim that the true parameter value is not included in the 100(1 - α)% confidence interval.

It is provided that 255 students create the same confidence interval, correctly.

Then the number of students we expect to have an interval that does not contain the true mean value is,  255\times [\alpha\%]

For instance, if the students are creating a 95% confidence interval for mean then the number of students we expect to have an interval that does not contain the true mean will be:

The significance level is:

Confidence\ level=100(1-\alpha)\\\frac{95}{100}=(1-\alpha)\\\alpha =1-0.95=0.05

Number of students we expect to have an interval that does not contain the true mean will be: 255\times [\alpha\%]=255\times 0.05=12.75\approx13

Thus, 13 of the 255 confidence intervals will not consist the true mean value.

3 0
3 years ago
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