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Masteriza [31]
3 years ago
10

The fitness center needs $125,000 in five years for more workout machines. Find the total interest earned if payments are made a

t the end of each quarter with interest at 6% compounded quarterly.
Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

$38,562.5

Step-by-step explanation

Using the compound interest formula

A = P(1+r/n)^nt

P is the principal = $125,000

r is the rate = 6% = 0.06

time t  = 5years

n = 0.25 (quarterly payment)

Substitute

A = 125000(1+0.06/0.25)^5(0.25)

A = 125000(1+ 0.24)^1.25

A = 125000(1.24)^1.25

A = 125000(1.3085)

A = 163,562.5

Hence the interest earned = 163,562.5 - 125000

interest earned = $38,562.5

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Answer:

50th term would be 317

Step-by-step explanation:

The "shortcut" would be 17+6x since you have a starting value of 17 and you add 6 to each term.

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-3h=18-27h
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based on the simulation, what is the probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to
Triss [41]

Using the binomial distribution, supposing that 0.3 of the callers have to wait more than 8 minutes to have their calls answered, it is found that there is a 0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

For each caller, there are only two possible outcomes, either they have to wait more than 8 minutes to have their calls answered, or they do not. The probability of a caller having to wait more than 8 minutes is independent of any other caller, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 10 callers, hence n = 10
  • Suppose that 0.3 of them have to wait more than 8 minutes, hence p = 0.3

The probability that <u>at most 2</u> of the next 10 callers will have to wait more than 8 minutes is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.0282

P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.1211

P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.2335

Then:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0282 + 0.1211 + 0.2335 = 0.3828

0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

A similar problem is given at brainly.com/question/25537909

3 0
3 years ago
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Answer:

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Urn U1: 3 red and 2 yellow marbles, in total 5 marbles.

The probability to select red marble is \dfrac{3}{5}=0.6.

Urn U2: 3 red and 7 yellow marbles, in total 10 marbles.

The probability to select red marble is \dfrac{3}{10}=0.3.

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The probability to select red marble is \dfrac{1}{5}=0.2.

The probability to choose each urn is the same and is equal to \frac{1}{3}.

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