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melisa1 [442]
3 years ago
8

5. If possible, find the missing side length labeled with a question mark. If no possible,explain why

Mathematics
1 answer:
lawyer [7]3 years ago
3 0

Answer:

10

Step-by-step explanation:

I think is 10 because they are different triangles but both with the same measure, as you can see both angles are the same [36] and both sides of the triangle too [6] so when you divide the base [20] by 2 , 20÷2=10

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What may be revealed from a scatterplot?a. No relationship between two variables b. A linear relationship between two variables
ruslelena [56]

Answer:

d

Step-by-step explanation:

d

6 0
4 years ago
Convert 25/8 into a mixed number
motikmotik
Changing improper fractions to mixed form or mixed numbers is a very simple thing. You just have to follow the following:
Then write Let us have 25/8. <span><span>
1.       </span><span>Divide the numerator (top number)  by the denominator (number below the bar). </span></span> Simply divide 25 by 8. 25 ÷ 8 = n
We can have 3 and 1 as a remainder. So, the answer will be 3 and 1/8. <span><span>

2.       </span> <span>Write down the whole number answer. 
Since we have 3 as the whole number answer, write it down. And;</span></span> <span><span>

3.       </span><span> Write down any remainder above the denominator, like this:</span></span> 3 and 1 (remainder) over 8 (denominator of the given improper fraction). That is, 3 1/8  


3 0
4 years ago
What two step equation when solved does x=-3
Travka [436]

Answer:

x + 3 = 0.

Step-by-step explanation:

One would be:

x + 3 = 0        Subtract 3 from both sides:

x + 3 - 3 = 0 - 3

x = -3

7 0
3 years ago
(x2y-3y2+5xy2)-(-x2y+3xy2-3y2)
Reil [10]
2x2y+8xy2-6y2 .........
8 0
3 years ago
Solve the following question
White raven [17]

Answer:

g) u^{4}\cdot v^{-1}\cdot z^{3}, h) \frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) \frac{u^{5}\cdot v}{z}\div  \frac{u\cdot v^{2}}{z^{4}}

1) \frac{u^{5}\cdot v}{z}\div  \frac{u\cdot v^{2}}{z^{4}} Given

2) \frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} } Definition of division

3) \frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}   \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}

4) \left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)  Associative property

5) u^{4}\cdot v^{-1}\cdot z^{3}   \frac{a^{m}}{a^{n}} = a^{m-n}/Result

h) \frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}

1) \frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10} Given

2) \frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} } Definition of division

3) \frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}  \frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}

4) \frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) } Factorization/Distributive property

5) \left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right] Modulative and commutative properties/Associative property

6) \frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}  \frac{a^{m}}{a^{n}} = a^{m-n}/\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}/Definition of division/Result

3 0
3 years ago
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