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shutvik [7]
3 years ago
15

-6=8x-14 show all steps please

Mathematics
2 answers:
nikitadnepr [17]3 years ago
6 0

Answer:

1=x

Step-by-step explanation

Add 14 to both side(because it is opposite)

-6=8x-14

+14       +14

8=8x

Divide both sides by 8

8/8=8x/8

1=1x(or just 1=x)

astraxan [27]3 years ago
6 0

The answer will be X=1.

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Write in mathematical expression.
bulgar [2K]

Answer:

B

Step-by-step explanation:

1) "number multiplied by -6" = number times -6 (x is the number)

-6 * x = -6x

2) "subtracted from the sum of (8 and two times the number)"

sum is addition

two times x(the number) plus 8

2x + 8

3) -6x is being subtracted from 2x + 8

2x + 8 - (-6x) =

2x + 8 + 6x =

8x + 8

B. 8x + 8

4 0
3 years ago
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Step-by-step explanation:


6 0
4 years ago
Which of the following is the statement below describing? If a point is on the perpendicular bisector of a segment, then it is e
Bezzdna [24]

Answer:

(C) Perpendicular bisector theorem

Step-by-step explanation:

(A) Right angle theorem : The right angle theorem states that if two angles are supplementary and congruent, then these two angles are right angles.

(B) Converse of perpendicular bisector theorem: The converse of  perpendicular bisector theorem states that If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of that segment.

(C) Perpendicular Bisector Theorem: The Perpendicular Bisector Theorem states that  If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.

(D) Pythagorean theorem: The Pythagorean theorem states that in the right angled triangle, the square of the hypotenuse of the triangle is equal to the sum of the squares of the other two sides that is:

(Hypotenuse)^2=(Base)^2+(Perpendicular)^2

Since, the given statement is the statement of the Perpendicular bisector theorem, thus  option C is correct.

3 0
3 years ago
Read 2 more answers
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Step-by-step explanation:

The value of x can be written in terms of W only since both are variable

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alexgriva [62]
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