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vekshin1
3 years ago
10

25 - (10 = 5) = 1. 3 2. 5 3.20 4. 23 Please help me:)

Mathematics
1 answer:
Illusion [34]3 years ago
4 0

Answer:

if the question is 25-{10-5}

then the answer is 25-5

20

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Solve 3kx + 24 = 9 kx for x.
uranmaximum [27]

Answer:

Step-by-step explanation:

3kx + 24 = 9kx

First subtract 3kx to both sides.

24 = 9kx  - 3kx

24 = 6kx

Divide both sides by 6

24/6 = kx

4 = kx

Divide both sides by k.

4/k = x

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3 years ago
Add. -85.53+(-41.00) <br><br> A. -126.53<br> B. -44.47<br> C. 44.53<br> D. 126.47
Rashid [163]
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3 years ago
What is the next three numbers in this pattern 10 5 20 10 40
grigory [225]
10, 5, 20, 10, 40, 20, 80, 40, 160, 80,

Next Three Numbers:  20, 80, 40

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Divide 20 by 4 to get 10

Multiply 10 by 4 to get 40
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3 0
4 years ago
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Can someone please answer this
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3 years ago
Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position
nexus9112 [7]

Answer:

\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60

Step-by-step explanation:

So, we know that:

\tan(\theta)=60/11\text{ and } 90\textdegree

Since θ is in QI, this means that <em>all</em> of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the <em>opposite side to the adjacent side</em>. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

a^2+b^2=c^2

Substitute 60 for a and 11 for b:

60^2+11^2=c^2

Solve for c. Square both numbers:

3600+121=c^2

Add:

c^2=3721

Take the square root of both sides:

c=61

Therefore, the hypotenuse is 61.

So, our side lengths are: Opposite=60; Adjacent=11; and Hypotenuse=61.

Now that we know the lengths, we can find the other trig ratios:

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 60 for Opp and 61 for Hyp:

\sin(\theta)=60/61

Cosecant is the reciprocal of sine. So:

\csc(\theta)=61/60

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 11 for Adj and 61 for Hyp:

\cos(\theta)=11/61

Secant is the reciprocal of cosine. So:

\sec(\theta)=61/11

Tangent and Cotangent:

We are already given that tangent is:

\tan(\theta)=60/11

Cotangent is the reciprocal of tangent. So:

\cot(\theta)=11/60

4 0
4 years ago
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