The volume of a rectangular prism having length 5 m, width 6 m, and the height 8 m, is?
1 answer:
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Answer:
a. t`= 7.63
b.υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1
= 18.885 ≈19 The degrees of freedom is always rounded in this calculation.
c. The critical region for one tailed test for alpha= 0.1 and 19 degrees of freedom is 1.328= 1.33
The critical region is ║t║` ≥ t 0.05,19 = 1.729= 1.73
A. Reject H0 because the computed tSTAT test statistic is greater than the upper-tail critical value
Step-by-step explanation:
Answer:
Step-by-step explanation:
We state our null and alternative hypothesis as
H0: μ1=μ2 against Ha: μ1 ≠ μ2
The level of significance is α=0.1
Since the population have unequal variances , the test statistic if H0 is true ,is
t`= x1`- x2`/ √s₁²/n1 + s₂²/n2
which has approximately a t- distribution with υ degrees of freedom where
υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1
Computations:
t`= x1`- x2`/ √s₁²/n1 + s₂²/n2
t`= 46-31/ √4²/9 + 5²/12
t`= 15/√16/9 +25/12
t`= 15/ √64+75/36
t`=15/1.9649
t`=7.6339
t`= 7.63
υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1
= [139/36]²/ (16/9)²/8 +(25/12)²/11
= 14.91/ 0.395 + 0.395
= 18.885
≈19 The degrees of freedom is always rounded in this calculation.
The critical region is ║t`║≥ t 0.05,19 = 1.729
Since the calculated value of t` falls in the critical region we reject our null hypothesis of equal means.
