Answer:
Option d) 115 degrees
Step-by-step explanation:
We are given a trapezium ABDE in the picture. AB and ED are the parallel sides.
F is the mid point of AE and C the midpoint of BD. FC is joined.
We are also given that angle of AED = 65 degrees.
To find the measure of angle BAE.
Since sides AB and ED are parallel sides we find that AE is the transvesal intersecting the two parallel lines.
Hence by parallel lines axiom, the two interior angles namely Angle AED and BAE are supplementary.
i.e. 65 +angle BAE=180
Hence angle BAE = 115 degrees.
Option d is the answer.
Part A: D) x is positive, y is negative.
Part B: C) both x and y are negative.
Part A:
P' is found by rotating P 90° counterclockwise about the origin. This makes the coordinates (x,y) transform to (-y,x). Thus (-2,-1) maps to (1,-2).
Part B:
Q'' is found by rotating Q 90° counterclockwise about the origin, then reflecting across the x axis. This makes the coordinates (x,y) first transform to (-y,x), then makes the new y-coordinate the opposite sign. Thus (1,2) first maps to (-2,1), then to (-2,-1).
(2x^2/(1-x^2)) + 3^(1/x) for the first half you can simply divide all terms by the highest power of x to get:
2/(1/x^2-1) as x approaches infinity you have 2/-1=-2
For the second part the exponent approaches zero as x approaches infinity and anything raised to the zero power is equal to 1 so you have:
-2+1=-1
So the limit as x approaches infinity is -1.
Answer:
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