Declan says that for any number n, the product 4 x n is greater than 4. Which value of n shows why Declan is incorrect?

Mathematics

1 answer:

Sindrei [870]3 years ago

6 0

Answer:

A negative number or zero

Step-by-step explanation:

A negative number or zero will result in a product less than 4.

4 * 0 = 0

0 < 4

4 * -1 = -4

-4 < 4

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What is the product (9t-4)(-9t<br> -4)

r-ruslan [8.4K]

Hey Tro2,

Lets find the product of your equation together,

The question we are encountering is : What is the product (9t-4)(-9t<span>-4)?

Lets simplify this step by step, shall we.

$\left(9t-4\right)\left(-9t-4\right)$ : Equation

$\mathrm{Distribute\:parentheses\:using}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$ .

Where : $a=9t,\:b=-4,\:c=-9t,\:d=-4$ .

This leads to $9t\left(-9t\right)+9t\left(-4\right)-4\left(-9t\right)-4\left(-4\right)$ .

Now we have to $\mathrm{Apply\:minus-plus\:rules}$ .

</span>Where: $-\left(-a\right)=a,\:\:\:\:+\left(-a\right)=-a$

$-9t\cdot \:9t-9t\cdot \:4+4\cdot \:9t+4\cdot \:4$

$=-81t^2+16$

7 0

4 years ago

Read 2 more answers

• I need help With This & a explanation!

KatRina [158]

The answer is C=10

This is the Pythagorean theorem, it solves for the hypontunuse. Basically it tells you the missing sides length.

It’s really simple once you get the hang of it. The formula is

A^2+b^2=c^2

Plug in the side lengths you have (6 and 8)

6^2+8^2=c^2

36+64=c^2