<span>the sum of three consecutive odd integers is 69. Find the integers.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:</span>2x-1 + 2x+1 + 2x+3 = 69<span>
</span><span>6x + 3 = 69
2x + 1 = 23
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So 2x-1 = 21
And 2x+3 = 25
</span><span>let:
x be the first odd integer
x + 2 be the 2nd odd integer
x + 4 be the 3rd odd integer
solution:
1st odd integer + 2nd odd integer + 3rd odd integer = 69
x + (x+2) + (x+4)= 69
</span>
<span>3x + 6 = 69
3x = 69 - 6
3x = 63 (dividing both sides by three)
x = 21
_______________________________________
x=21
x+2=23
x+4=25
therefore, the 1st integer is 21, the 2nd is 23 and the 3rd is 25..</span>
Answer:
The correct answer is the first one of your list of options:
"<em>Locate the ordered pair (0, –6). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points</em>."
Step-by-step explanation:
Since the y-intercept is -6, then the point (0, -6) is a point on the line.That is x = 0 and y = -6. From there you move according to the slope value "2 = 2/1" which means two units of rise when the run is one.
Then, from (0, -6) move up 2 units and then right one unit. The new point should also be a point on the line. Join the two points with a line to graph the function.
