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slega [8]
3 years ago
14

I swear. I’m just lazy. LOL XD

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0
The answer is A
Med range = 65+15 /2 = 40
Range = 65-15=50
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10th of a second : A. 60.34 = 60.3 B. 60.32 = 60.3 C. 60.33 = 60.3 D.
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3 years ago
I need to turn this in in 2 hours please hurry
Nuetrik [128]

Answer:

  2) 162°, 72°, 108°

  3) 144°, 54°, 126°

Step-by-step explanation:

1) Multiply the equation by 2sin(θ) to get an equation that looks like ...

   sin(θ) = <some numerical expression>

Use your knowledge of the sines of special angles to find two angles that have this sine value. (The attached table along with the relations discussed below will get you there.)

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2, 3) You need to review the meaning of "supplement".

It is true that ...

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This latter relation is the one applicable to this question.

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Similarly, it is true that ...

  cos(θ) = -cos(θ+180°),

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As above, it is this latter relation that applies to problems 2 and 3.

6 0
3 years ago
What is 275 divided by 38
Triss [41]

Answer:

The answer is 7.2368421053 .

6 0
3 years ago
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HELP ASAP ILL GIVE BRAINLIST
tankabanditka [31]

Answer: I think the answer would be (2, -1)

8 0
3 years ago
What is the kinetic Energy of a 110 kg linebacker rushing towards his football
Leviafan [203]

<u>Answer:</u>

The Kinetic energy of the 110 kg linebacker is 1375 J

<u>Solution:</u>

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

KE=\frac{1}{2} \times m v^{2}

Here, The linebacker’s mass m = 110 kg

The linebacker’s velocity v = 5 m/s

So by substituting the values,

The kinetic energy of linebacker is

K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules

3 0
3 years ago
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