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kari74 [83]
3 years ago
7

PLEASE HELP!!!!

Mathematics
2 answers:
Basile [38]3 years ago
4 0

Answer:

D

Step-by-step explanation:

edge

scZoUnD [109]3 years ago
3 0

Answer:

(D) 1+0.06m

Step-by-step explanation:

Let's say that m=$120

(A)= $127.2

(B)= $127.2

(C)= $127.2

(D)= $8.2

As you can see after I substituted in 120 for (m) and solved, D is the only equation that did not represent her current balance.

I hope this helps!

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Which number line models the expression -3 + 5 ?
damaskus [11]
I think the answer would be B
3 0
3 years ago
A series of quarterly payments of P1,300 each at the first payment is due at 4 years, and the last payment at the end of 12 year
gtnhenbr [62]

Answer:

The Value of Payments is  P18,557.15

Step-by-step explanation:

The quarterly payment is an annuity payment.

Use the following formula to calculate the present value of the payments.

PV of Annuity = Annuity Payment x ( 1 - ( 1 + interest rate )^-Numbers of periods ) / Interest rates

Where

Annuity Payment = Quarterly payment = P1,300

Interest rate = 5.12% x 3/12 = 1.375%

Numbers of periods = 4 years x 12/3 = 16 quarters

PV of Annuity = Value of Payments  = ?

Placing values in the formula

Value of Payments = P1,300 x ( 1 - ( 1 + 1.375% )^-16 ) / 1.375%

Value of Payments =  P18,557.15

4 0
3 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
2 years ago
Translate to an algebraic expression. 26 more than q
Umnica [9.8K]
A= 26 > q

if it says 26 grader than it means the mouth opens to that 26
if it says 26 less then it means the mouth is facing to the q
but it is not so it is the mouth facing the 26
6 0
2 years ago
In an on-line survey, a school learns that 77 of 100 parents prefer to receive the newsletter electronically. How many paper new
Kay [80]
77% of the school want electronic newsletters, so 23% of the school want physical paper newsletters.

77% of 650 is 500.5.
23% of 650 is 149.5.

650/100 = 6.5
6.5x77 = 500.5
6.5x23 = 149.5

It's best to round that figure up to 150 as there will not be a parent who only needs half of the newsletter.
5 0
2 years ago
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