Answer:
He owned Cat for 5 years.
Step-by-step explanation:
Given: Owned dog for 9 years.
Dog owned year is one year less than twice as long as he owned a cat.
Lets assume the years that cat has been owned be "x".
Now, finding the number years that Cat hes been owned.
As given, Dog owned year is one year less than twice as long as he owned a cat.
∴ using equation to find the Cat´s owned years.
⇒ 
adding 1 on both side.
⇒ 
dividing both side by 2
⇒
∴x= 
Hence, Cat has been owned for 5 years.
Answer: 1,594,323
Step-by-step explanation:
No of leaves which falls daily on the first day = 1
No of days leaves falls = 14 days.
Solution:
No of leaves of day 1
= 1.
No of leaves on day 2
= 1*3
= 3
No of leaves of day 3
= 3*3
= 9
No of leaves of day 4
= 9*3
= 27
No of leaves on day 5
= 27*3
= 81
No of leaves on day 6.
= 81*3
= 243.
No of leaves of day 7
= 243*3
= 729
No of leaves on day 8
= 729 * 3
= 2187
No of leaves on day 9
= 2187 *3
= 6561
No of leaves on day 10
= 6561 * 3
= 19683
No of leaves on day 11
= 19683 * 3
= 59049
No of leaves on day 12
= 59049 *3
= 177147
No of leaves on day 13
= 531441
No of leaves on day 14
= 531441 * 3
= 1,594,323.
The number of leaves that would be on the ground on the 24th day of autumn would be 1,594,323
In a parallelogram, consecutive angles are supplementary.
3y + 78 = 180
3y = 102
y = 34
Answer:
5995 hugs
Step-by-step explanation:
This is a combination problem: we want to make groups of two monkeys, where a pair of monkey 1 and 2 is the same pair of monkey 2 and 1 (it is the same hug). So, if the total number of monkeys at the zoo is 110, we have a combination of 110 choose 2:
C(110,2) = 110! / (2! * (110-2)!) = 110 * 109 / 2 = 5995
So the total number of hugs is 5995
