All categories

3 years ago

Which number has the greatest absolute value?

Mathematics

2 answers:

Vitek1552 [10]3 years ago

5 0

Answer:

B. $|-8|$

Step-by-step explanation:

The definition of absolute value is:

$|x|=\left \{ {{-x}, x$

Then analyzing each option:

A. $|-3|=-(-3)=3$

B. $|-8|=-(-8)=8$

C. $|2|=2$

D. $|5|=5$

Then the number 8 (option B) has the greatest absolute value.

BabaBlast [244]3 years ago

3 0

Answer:

Sample Response: No, Riko is not correct. The points do not have the same x-coordinates. If you connect the points, they do not form a horizontal or vertical line, so you cannot count spaces or use absolute value to find the distance.

Step-by-step explanation:

It's the sample response.

You might be interested in

PLEASE HELP ASAP!!!!

zlopas [31]

Answer:

k - 5 = m

n - 3 = s

Lisa is 17 and Myra is 12

__________________________________________________

1) Key:

brother = b

me = m/n

sister = s

Equation:

m + 5 = b

m - 3 = s

Answer:

b - k = m

n - 3 = s

2)

L + M = 19

(L + 5) + M = 29

(L + 5 - 5) + m = 24

L + M = 24 / 2 = 12

L = 12 + 5 = 17

M = 12

Lisa will be 17 and Myra is 12

3 0

3 years ago

Read 2 more answers

help what is 3x+17=14

Brut [27]

To find the value of x we follow this:
3x+17=14
Take away 17 from both sides
3x=-3
Then divide by 3
x=-1

6 0

4 years ago

Read 2 more answers

Each spring, Rachel starts sneezing when the pear trees on her street blossom. She reasons that she is allergic to pear trees. F

horsena [70]

Answer:

Seasonal allergies

Step-by-step explanation:

She migtht have seaonal allergies

3 0

3 years ago

eight cards are drawn from a standard deck of 52 cards. how many hands off with cards contain exactly three queens and three jac

d1i1m1o1n [39]

Answer:

15,136 hands off with cards contain exactly three queens and three jacks.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Standard deck:

4 queens and 4 jacks.

The other 52 - 8 = 44 cards are neither queens nor jacks.

Wow many hands off with cards contain exactly three queens and three jacks?

3 queens from a set of 4.

3 jacks from a set of 4.

2 other cards(not queens neither jacks) from the other 44. So

$C_{4,3}C_{4,3}C_{44,2} = \frac{4!}{1!3!} \times \frac{4!}{1!3!} \frac{44!}{2!42!} = 4*4*22*43 = 15136$

15,136 hands off with cards contain exactly three queens and three jacks.

4 0

3 years ago

john is twice as old as mary. the sum of their ages is 21. how old is mary? let j = john's age and m = mary's age. select the sy

Verdich [7]

Hello,

let's assume j the john's age, m the mary's age.

"John is twice as old as mary"==>j=2*m

"the sum of their ages is 21" ==>j+m=21

==>2*m+m=21
==>3m=21
==>m=7
and j=21-7=14

3 0

4 years ago