Based on the seed experiment in the Poop Lab, the seeds that are expected to sprout are the seed in the elephant poop while the seeds in the soil are not expected to sprout.
<h3>What was the Poop Lab?</h3>
The main idea of the Poop Lab is to compare the growth of seeds that have gone through the digestive system of an animal, in this case, an elephant, to a seed that has not.
The seed that had gone through the digestive system was observed to have sprouted but the seeds in the soil did not. This experiment demonstrates the role animals such as elephants play in shaping the ecosystem through seed dispersal.
The seed that passed through the digestive system of the element and then passed out into the poop received enough nutrients for growth.
However, the seed in the soil does not receive adequate nutrients.
Learn more about seed growth at: brainly.com/question/29316564
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<span>Proto-oncogenes are genes that normally help cells grow. When a proto-oncogenemutates (changes) or there are too many copies of it, it becomes a "bad" gene thatcan become permanently turned on or activated when it is not supposed to be. When this happens, the cell grows out of control, which can lead to cancer.....Is this what you need ?</span>
About 2.5 % I think maybe if your talking about fresh water
Answer:
The frequency of A1 be on Big Pine Key after a single generation of migration from No Name Keyp is 0.2276
Explanation:
Whenever it occurs migration between two populations, there is genetic flux going on. Genetic flux might be considered as an evolutive strength only if migration > 0 and if the allelic frequency in one generation is different from the allelic frequency in the next generation.
Genetic flux acts homogenizing the allelic frequencies between the two populations, and it might introduce variability.
By knowing the allelic frequencies in both populations at a certain time and the migration rate, we can calculate the allelic frequencies of populations in the next generation. This is:
pA₂=pA₁(1-m)+pB₁ m
pB₂=pB₁(1-m)+pA₁ m
Being
- A one population and B the other population
- pA₁ and pB₁ the frequencies of the p allele before migration,
- pA₂and pB₂ the frequencies of the p allele after migration,
- m the migration rate
In the exposed example, we know that:
- No Name Key population allelic frequency: A1 = 0.43 and A2 = 0.57
- Big Pine Key population allelic frequency: A1 =0.21 and A2 = 0.79
Let´s say that p represents A1 allele, and q represents A2 allele.
The frequency of A1 allele (p) be on Big Pine Key (Population B) after a single generation of migration from No Name Key (Population A)
pB₂=pB₁(1-m)+pA₁ m
pB₂=0.21 x (1 - 0.08) + 0.43 x 0.08
pB₂= 0.2276
The allelic frequency in a population after one generation is the allelic frequency of individuals of that population that did not migrate (21 x (1 - 0.08) plus the allelic frequency of the new individuals that came from the other population (0.43 x 0.08).
You can corroborate your result by calculating the q allele frequency in the next generation and summing both of them up. The result should be one.
qB₂= qB₁(1-m)+qA₁ m
qB₂= 0.79 x (1 - 0.08) + 0.57 x 0.08
qB₂= 0.7724
p + q = 1
0.2276 + 0.7724 = 1
