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Blababa [14]
3 years ago
8

I'm feeling generous so whoever answers this easy problem correct, I'll give you brainliest :)

Mathematics
2 answers:
ratelena [41]3 years ago
4 0

Answer:

4 haha...............

11111nata11111 [884]3 years ago
3 0

Answer:

4! also u seem like a super nice person

Step-by-step explanation:

You might be interested in
the interest paid for borrowing qn amount of money for 3yrs at the rate of 4%is n108 find the amount of the money borrowed
tankabanditka [31]

Answer:

$864.94

Step-by-step explanation:

So the amount of money over time can be given with an exponential function y=a(b)^x or more specifically y=a(1+r)^x    where r is the growth rate (interest rate)

So the equation can be written as

m= P(1.04)^t    where m represents the amount of money over time, P represents the principle amount, and t represents time in years. Since we're given the amount of interest paid and not the total amount which includes the initial amount borrowed you have to subtract P from the equation. This will give us the equation that we'll use to find the initial amount

I = P(1.04)^t-P  where I represents the interest paid.

plug the values into the equation

108 = P(1.04)^3-P\\108 = P(1.124864) - P\\108 = 0.124864P\\\\864.941 = P

3 0
2 years ago
HELP!! PLEASE!!! THIS IS DUE TOMORROW
faltersainse [42]
A. Skewed right

B. Symmetric(bell shaped)

C. Skewed Left

D. Symmetric(U Shaped)

7 0
3 years ago
A progression has a second term of 96 and a fourth term of 54. Find the first term of the progression of the progression is arit
Vladimir79 [104]

Here, we are required to find the first term of an arithmetic progression which has a second term of 96 and a fourth term of 54.

  • The first term of the progression which has a <em>second term</em> of 96 and a <em>fourth term</em> of 54 is; a = 117.

<em>In Arithmetic progression, the N(th) term of the progression is given by the formular;</em>

T(n) = a + (n-1)d

where;

  • a = first term

  • d = common difference.

  • n = nth term.

Therefore, from the question above;

  • T(2nd) = a + d = 96..............eqn(1)

  • and T(4th) = a + 3d = 54..........eqn(2)

By solving the system of equations simultaneously;

we subtract eqn. 2 from 1, then we have;

<em>-2d = 42</em>

Therefore, d = -21.

However, the question requests that we find the first term of the progression; From eqn. (1);

a + d = 96

Therefore,

  • a - 21 = 96
  • a = 96 + 21

Ultimately, the first term of the progression is therefore; a = 117

Read more:

brainly.com/question/18828482

5 0
3 years ago
What is the range of the function f(x) = -|X - 4| + 5?
Law Incorporation [45]

Answer:

Range = (-<em>∞, 5</em>)

Step-by-step explanation:

This is the absolute value function with transformation.

The parent function is f(x) = |x|

This function has a "negative" in front, so it makes it reflect about x axis

The -4 after x makes horizontal translation of 4 units right

the +5 at the end makes the function translate 5 units UP

<em>The graph is shown in the attached picture.</em>

<em>Looking at the graph, we can clearly see the range. The range is the allowed y-values. Hence, we can see that the </em><em>range is  -infinity to 5</em>

<em />

<em>answer is not properly given, so i can't choose from the options, but the answer is -∞, 5 to 5</em>

3 0
4 years ago
A manufacturer makes chocolate squares that have a target weight of 8 g. Quality control engineers sample 30 chocolate squares t
posledela

Using the <em>normal distribution and the central limit theorem</em>, it is found that the power of the test is of 0.9992 = 99.92%.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is \mu = 8.5.
  • The standard deviation is \sigma = 0.87.
  • A sample of 30 is taken, hence n = 30, s = \frac{0.87}{\sqrt{30}} = 0.1588.

The power of the test is given by the probability of a sample mean above 8, which is <u>1 subtracted by the p-value of Z when X = 8</u>, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem:

Z = \frac{X - \mu}{s}

Z = \frac{8 - 8.5}{0.1588}

Z = -3.15

Z = -3.15 has a p-value of 0.0008.

1 - 0.0008 = 0.9992.

The power of the test is of 0.9992 = 99.92%.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

5 0
3 years ago
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