The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. Hakeem is building the deck and decided to

Question

4 years ago

8

The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. Hakeem is building the deck and decided to

increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?
A. x^2 + 12x + 27
B. x^2 + 9x + 18
C. x^2 + 9x
D. x^2 + 6x

SAT

2 answers:

Andrei [34K] · Answer 1 · 2021-12-23T18:29:23+03:00

Andrei [34K]4 years ago

8 0

The original length and width:
Length x + 6
Width x

Hakeem increased both dimensions by 3 feet, so they now are
Length x + 9
Width x + 3

To find the new area, multiply (x + 9) and (x + 3)
It is $x^2 \+ 12x \+ 27$
So, the answer is A.

Orlov [11] · Answer 2 · 2021-12-23T17:16:41+03:00

Orlov [11]4 years ago

6 0

Im not 100% sure but im like 98% sure that the answer is C. Sorry I couldnt give you a FOR SURE answer but im pretty sure thats the answer. hopefully someone else comes soon to give you the for sure but i think c is the answer.