Answer:
D
Explanation:
If pets are on leashes and the owner is paying a good amount of attention toward the pets to make sure they don't get loose, the pets should remain calm and not cause an disturbances.
So the most logical option is D.
This excerpt most clearly conveys Lady Bracknell’s belief that wealth makes someone more desirable.
- From the story "The importance of being Earnest",. a conversation bean between Mr. Worthing and Lady Bracknell's about Miss Cardew as to if she had little fortune or not.
- When the response came that Miss Cardew had about hundred and thirty thousand pounds in the funds and not not as little as she had taught. This alone spike the interest of Lady Bracknell as she later regard Miss Cardew as the most attractive young lady.
Conclusively we cay say that this excerpt most clearly conveys Lady Bracknell’s belief that wealth makes someone more desirable.
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Molly could possibly get the car of her dream by using the Hire Purchase (HP) Using Hire Purchase method.
<h3>What is Hire Purchase ?</h3>
In simple term hire purchase is a contract between two parties, usually the customer and the seller of an item, the customer/buyer agrees to pay for an item in instalments.
It should be noted that the item belongs to the customer until the item is completely paid for by the buyer.
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Using the normal distribution, it is found that there is a 0.963 = 96.3% probability that on a given day, his commute will be longer than 49 minutes.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
.
The probability that on a given day, his commute will be longer than 49 minutes is <u>one subtracted by the p-value of Z when X = 49</u>, hence:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{49 - 57}{4.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B49%20-%2057%7D%7B4.5%7D)
Z = -1.78
Z = -1.78 has a p-value of 0.0375.
1 - 0.0375 = 0.963.
0.963 = 96.3% probability that on a given day, his commute will be longer than 49 minutes.
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