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Len [333]
3 years ago
8

1 of 10

Mathematics
1 answer:
lana [24]3 years ago
5 0

Answer:

$46

Step-by-step explanation:

5 X 8 = 40

now add shipping

40 + 6 = 46

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3x+2y+4z=12 X+y+2z=6 (X=0,y=4,z=1) Determine if the given 2 lines intersect at the given point. Explain your reasoning. -2x-4y+z
IgorC [24]
Equation 1: 3x + 2y + 4z = 12
Equation 2: x + y + 2z = 6

Substituting x = 0, y = 4 and z = 1 into equation 1 and equation 2 and if the answer equals to 12 and 6 then the two lines intersect at the given point

Equation 1 ⇒ 3(0) + 2(4) + 4(1) = 0 + 8 + 4 =12
Equation 2 ⇒ 0 + 4 + 2(1) = 4 + 2 = 6

We have the answer of 12 and 6, hence the two lines intersect at the given point
-------------------------------------------------------------------------------------------------------------

Equation 1: -2x - 4y + z = 8
Equation 2: 4x + 2y = -5

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Equation 2 ⇒ 4(-2) + 2(0) = -8 + 0 = -8

The answers are not 8 and -5 hence the lines don't intersect at given point
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It’s as you can seeB .162.
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Read 2 more answers
Which one doesn’t belong? Why? Explain. please help me
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Hi again! I'm assuming that the straight line, which I believe is for y = -2 doesn't belong because everything else has two lines, I mean like it reflects off a certain point on the x or y axis but b)  [as I like to call it] doesn't reflect on another axis.

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