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daser333 [38]
2 years ago
14

Please help me with this question??m

Mathematics
1 answer:
Keith_Richards [23]2 years ago
7 0

Answer:

75

Step-by-step explanation:

f(1) = 7

f(n) = 3f(n-1) + 3

So what you are trying to do here is find the recursive value (that's what it is called) for f(n). Computers love this sort of thing, but we humans have to do it slowly and carefully.

So let's try f(2)

That means that f(2) = 3*f(n-1) + 3

but if f(2) is used it means that you have to know f(2-1) which is just f(1) and we know that.

so f(2) = 3*f(1)+3

f(2) = 3*7 + 3

f(2) = 21 + 3

f(2) = 24

Now do it again. We now know F(2), so we should be able to find f(3)

f(3) = 3*f(3 - 1) + 3  

f(3) = 3*f(2) + 3      We know that f(2) = 24

f(3) = 3* 24 + 3

f(3) = 72 + 3

f(3) = 75

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A square pyramid. The square base has side lengths of 6 inches. The 4 triangular sides have a base of 6 inches and height of 9 i
Marrrta [24]

Answer:

The area of the pyramid’s base is 36 in².

The pyramid has 4 lateral faces.  

The surface area of each lateral face is 27 in².

Step-by-step explanation:

"<u>Lateral</u>" means side, so the lateral faces are <u>triangles</u>.

The <u>base</u> is the bottom, which is a <u>square</u>.

To calculate the <u>area of the base</u>, use the formula for area of a square.

A_{base} = s^{2}

A_{base} = (6 in)^{2}

A_{base} = 36 in^{2}

To calculate the <u>area of a lateral face</u>, find the area of a triangle.

A_{lateral} = \frac{bh}{2}

A_{lateral} = \frac{(6 in)(9 in)}{2}

A_{lateral} = \frac{54 in^{2}}{2}

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In a pyramid, the number of lateral faces is the same as the number of sides in the base. <u>The square base as 4 sides, so there are 4 lateral faces</u>.

3 0
3 years ago
If f(x) =4 x-20 , what is f(4)
jolli1 [7]
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5 0
3 years ago
Use special right triangles to find the exact value (no decimals).
fgiga [73]

Let’s find some exact values using some well-known triangles. Then we’ll use these exact values to answer the above challenges.

sin 45<span>°: </span>You may recall that an isosceles right triangle with sides of 1 and with hypotenuse of square root of 2 will give you the sine of 45 degrees as half the square root of 2.

sin 30° and sin 60<span>°: </span>An equilateral triangle has all angles measuring  60 degrees and all three sides are equal.  For convenience, we choose each side to be length 2.  When you bisect an angle, you get 30 degrees and the side opposite is 1/2 of 2, which gives you 1.  Using that right triangle, you get exact answers for sine of 30°, and sin 60° which are 1/2 and the square root of 3 over 2 respectively.

Now using the formula for the sine of the sum of 2 angles,

sin(A + B) = sin A cos<span> B</span> + cos A sin B,

we can find the sine of (45° + 30°) to give sine of 75 degrees.

We now find the sine of 36°, by first finding the cos of 36°.

<span>The cosine of 36 degrees can be calculated by using a pentagon.</span>

<span>that is as much as i know about that.</span>

5 0
3 years ago
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