When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
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Answer:
15
Step-by-step explanation:
The first ratio is 1:3
12/36 = 3
So,
5 x 3 = 15
Mean is the average, mode is the number that is repeated most often and the median is the middle number. We know there are 5 numbers so, 5 is the middle as it is the median #. The mode has to appear more than once or 5 would also be a mode.
1 1 5 _ _
M = 1+1+5+x+y /5
4 = 1+1+5+x+y/ 5
4 = 7+x+y / 5
Average of 5 numbers is 4 therefore 4 times 5 = 20
20-7 = 13, what two numbers that are more than 5 equal 13? Only 6 &7.
4 = 1+1+5+6+7 / 5
