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Andrews [41]
3 years ago
8

Curriculum Exam

Computers and Technology
1 answer:
ella [17]3 years ago
3 0

Answer:

4,6

Explanation:

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The answer is an arrow
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Given the following adjacency matrix, what is the approximate rank vector after one iteration of the power iteration method (use
ValentinkaMS [17]

Note: The matrix referred to in the question is: M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

Answer:

a) [5/18, 5/18, 4/9]'

Explanation:

The adjacency matrix is  M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

To start the power iteration, let us start with an initial non zero approximation,

X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]

To get the rank vector for the first Iteration:

X_1 = MX_0

X_1 =  \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\

Multiplying the above matrix by 1/3

X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]

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How does classless inter-domain routing (cidr) help reduce waste of ip addresses?
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It allows for more accurate sizing of networks.
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In this exercise you will debug the code which has been provided in the starter file. The code is intended to do the following:
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Answer:

The corrected code is as follows:

import java.util.Scanner;

public class U2_L4_Activity_Two{

public static void main(String[] args){

Scanner scan = new Scanner(System.in);

String str1 = scan.nextLine();

String str2 = str1;

str1 = str1.toUpperCase();

System.out.println(str1);

System.out.println(str2);

}

}

Explanation:

This corrects the scanner object

Scanner scan = new Scanner(System.in);

This line is correct

String str1 = scan.nextLine();

This copies str1 to str2

String str2 = str1;

This converts str1 to upper case

str1 = str1.toUpperCase();

This prints str1

System.out.println(str1);

This prints str2

System.out.println(str2);

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This OS was created by a developer named Torvalds.
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The answer to this problem is Linux
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