Answer:
look at the pictures
Explanation:
1. If we cross the parental generation which is RR x rr, the probability of the F1 generation to get rough coat is 100% and they will be a carrier of the recessive trait smooth coat.
Since the phenotypic ratio is 100% heterozygous Rr, in crossing the F1 to get the F2, we will use the genotype Rr. To get the F2, use the cross Rr x Rr.
The phenotypic ration for F2 is 3:1. There is 75% to get rough coat and 25% smooth. The answer is based on the result on the Punnett square. On the other hand, the genotypic ratio is 1:2:1. There is 25% probability to get RR genotype, 50% Rr, and 25% rr.
2. Since the two parental mice got 6 albino offspring and 5 brown mice offspring, it is approximately 50%. it takes a parental mice who is Brown that is carrying an albino trait crossed with an albino to get offspring with almost the same number. Therefore, the genotype of the brown mice is Aa.
Do you have a full detailed question? Or perhaps a photo of the question?
Answer:
B (active transport using ATP)
Explanation:
Movement of substances normally occur in the direction of concentration gradient/difference i.e. the difference in concentration of a substance across a membrane. Letting molecules diffuse or pass down their concentration gradient does not require energy but pumping those molecules against gradient requires energy in form of Adenosine triphosphate (ATP). This process is called Active transport.
In order to perform certain cellular processes, cells need to move substances from their surroundings into the cell across their cell membrane. Moving this substances against the concentration gradient between the cell membrane and its extracellular fluid requires energy (ATP).
An example is the sodium-pottasium pump employed by animal cells in which they expend energy to move K+ molecules into the cell and Na+ molecules outside the cell against the concentration gradient of their cell membrane and extracellular solution.
To speed up chemical reactions by decreases the amount of energy needed In the reaction
Answer:
a. The operon is under positive control
a.) Loss of enzyme synthesis results from loss of regulatory R gene product which is regulated in the presence of Tis ophane for transcription. Absence of (Tis), transcription is positively controlled by regulatory Rprotein
b.) The proposed model reveals Tis / B complex prevents Tis enzymes from undergoing transcription through the RB operator by binding to the B region
the role of the R protein is
-decrease affinity of Tis / B complex to B region of RB
-bind to the R region on RB
- change the conformation of B region
- yield decreased affinity of Tis / B complex when R gene is lacking preventing transcription in the process
Effects of the RB mutations is that R protein will not bind to Tis / B complex to reduce transcription
