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Rainbow [258]
3 years ago
13

What values belong in the table shown below

Mathematics
1 answer:
sergiy2304 [10]3 years ago
7 0

Answer:

x=12 and y= 32

Hope it helps

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Question is attached​
Marina86 [1]

Answer:

ok

Step-by-step explanation:

6 0
3 years ago
Good points... just answer the question correctly​
NeTakaya

Answer:

R'(-9,4)  --------------- R'(9,-4)

Step-by-step explanation:

5 0
3 years ago
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If y is directly proportional to x² and y=2 when x=3 Find the value of y when x=6<br>Please Help
OlgaM077 [116]

Answer:

y = 8

Step-by-step explanation:

Given that y is directly proportional to x² then the equation relating them is

y = kx² ← k is the constant of variation

To find k use the condition y = 2 when x = 3, then

2 = k × 3² = 9k ( divide both sides by 9 )

\frac{2}{9} = k

y = \frac{2}{9} x² ← equation of proportion

When x = 6, then

y = \frac{2}{9} × 6² = \frac{2}{9} × 36 = 2 × 4 = 8

7 0
3 years ago
Use the given graph. Determine the period of the function.
Serhud [2]
The answer is 3. 

A period is the length that it takes  the graph to repeat in behavior. You'll notice that every 3 units, it hits the axis and repeats the same pattern. 
6 0
3 years ago
Read 2 more answers
A rectangular garden is 20 ft longer than it is wide. Its area is 3500 ft?. What are its dimensions?
Vladimir [108]

Answer:

width of the garden is 50 ft and the length is 70 ft

Step-by-step explanation:

Solution:-

- We will denote the width and and the length of the rectangular garden as:

   Width: x

   Length: x + 20

- We are given the area ( A ) of the garden is 3500 ft^2. We are to determine for what dimensions is the area A = 3500 ft^2.

- Recall that the area ( A ) of a rectangle is the product of length and width as follows:

                      A = Length * width

                      A = x*( x + 20 )

                      3500 = x^2 + 20x

                      x^2 + 20x - 3500 = 0

- Use the quadratic formula to determine the value of ( x ):

                     x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-20 +/- \sqrt{20^2 - 4*-3500} }{2}\\\\x = \frac{-20 +/- 120 }{2} = -10 +/- 60\\\\x = -70 , 50

- Ignore the negative value of ( - 70 ft ). Physical impractical to have a negative value. Hence, the width of the garden is 50 ft and the length is 70 ft

8 0
3 years ago
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