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Rainbow [258]
2 years ago
13

What values belong in the table shown below

Mathematics
1 answer:
sergiy2304 [10]2 years ago
7 0

Answer:

x=12 and y= 32

Hope it helps

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Si el lado de un cuadrado mide 10cm cuanto mide él área del círculo que se encuentra adentro de ese cuadrado
Alex17521 [72]

Answer:

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

Step-by-step explanation:

Para resolver este ejercicio tenemos que pensar que un cuadrado tiene sus 4 lados iguales, por lo que todos sus lados medirán 10cm.

Ahora nos fijamos que necesitamos saber para calcular el área de un circulo

a = área

r = radio

π = 3.14

a = π * r²

como podemos ver no sabemos el valor del radio

como el circulo toca con los 4 lados del cuadrado sabemos que su radio sera la distancia del centro del cuadrado a cualquiera de los lados.

Entonces tenemos que dividir un lado por 2

10cm/2 = 5cm

El radio del circulo sera 5cm

Ahora que tenemos todos los datos podemos calcular el valor del área

a = 3.14 * (5cm)²

a = 3.14 * 25cm²

a = 78.5cm²

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

8 0
3 years ago
Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
11Alexandr11 [23.1K]

Answer:

Oakdale

Step-by-step explanation:

The median can be seen inside the rectangle in the box-and whisker plot. It is the point in the middle, cutting the rectangle in two. Looking at the plots, Oakdale has a lower median.

4 0
3 years ago
What’s the correct answer for this? Select the ones that apply
faust18 [17]
First one and third one are both corrects that answer to your question and plz mark me Brainly it
7 0
2 years ago
NEED HELP NOW!! FOR MATH 10PTS
meriva

Answer:

a)

Step-by-step explanation:

Cost function = revenue function - profit function

   = -0.3x² + 150x - [-0.5x² + 250x - 300]

   = -0.3x² + 150x + 0.5x² - 250x +300

  = -0.3x² + 0.5x² + 150x - 250x + 300   {Combine like terms}

  = 0.2x² - 100x + 300

4 0
2 years ago
We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.
Juli2301 [7.4K]

Answer:

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

Null hypothesis:p\geq 0.8  

Alternative hypothesis:p < 0.8  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

\hat p=\frac{97}{110}=0.882 estimated proportion of students who completed the modules before class

p_o=0.8 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  2) Concepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%:  Null hypothesis:[tex]p\geq 0.8  

Alternative hypothesis:p < 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

5 0
3 years ago
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