if we take 31 to be the 100%, what is 28 off of it in percentage?
![\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 31&100\\ 28&x \end{array}\implies \cfrac{31}{28}=\cfrac{100}{x}\implies 31x=2800\implies x=\cfrac{2800}{31} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x\approx 90.32~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20amount%26%5C%25%5C%5C%20%5Ccline%7B1-2%7D%2031%26100%5C%5C%2028%26x%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B31%7D%7B28%7D%3D%5Ccfrac%7B100%7D%7Bx%7D%5Cimplies%2031x%3D2800%5Cimplies%20x%3D%5Ccfrac%7B2800%7D%7B31%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20x%5Capprox%2090.32~%5Chfill)
Answer:
3 and 2 i think
Step-by-step explanation:
Answer: could you make the question a little clearer
Step-by-step explanation:
Answer:
630,400,000
Step-by-step explanation:
630,379,982
The 3 above that is bold, between the 0 and the 7, is in the hundred thousands place.
To round to a place, change all digits to the right of that place to zero. If the digit immediately to the right is 0 through 4, you're done. If the digit immediately to the right is from 5 to 9, then you raise the digit you are rounding to by 1.
Step 1. Make all digits to the right of the hundred thousands digit 0.
630,300,000
Step 2. Since the digit immediately to the right of the hundred thousands digit was a 7, which is from 5 to 9, the digit we are rounding to goes up by 1. The 3 becomes 4.
630,400,000
Answer: 630,400,000