Answer:
Yes, it is a function
Step-by-step explanation:
Every possible input x value is paired with a unique output y value.
Another approach is to graph the function then conduct the VLT (vertical line test) at which point you will realize that any vertical line will intersect the graph at one point only meaning it is a function.
Hope this helps.
2x-3(0)=12
2x=12
x=6
(6,0)
2(0)-3y=12
-3y=12
y=-4
(0,-4)
2x-3(2)=12
2x-6=12
2x=18
x=9
(9,2)
ANSWERS: (6,0) (0,-4) (9,2)
Answer:
Step-by-step explanation:
I’m not sure if this is super accurate, but since P is prime, the only factors it has is 1 and itself, meaning that the square root of it will be irrational
Answer:
x = 2
Step-by-step explanation:
Taking antilogs, you have ...
2³ × 8 = (4x)²
64 = 16x²
x = √(64/16) = √4
x = 2 . . . . . . . . (the negative square root is not a solution)
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You can also work more directly with the logs, if you like.
3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2
3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents
6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify
2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)
ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2
2 = x . . . . . . . . . . . . . . . . . . . take the antilogs
Analytically, it will be
-√(1+1²) = -√2
The calculator shows it to be -1.41421356237
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= -√2 to 12 significant digits.