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9966 [12]
3 years ago
14

I need helppp could you help please pl,s pls pls pls pls pls plks pls pls pls pls pls pls

Mathematics
2 answers:
KengaRu [80]3 years ago
6 0

Answer:

(6, -4)

Step-by-step explanation:

x axis is before the y axis

Furkat [3]3 years ago
5 0

Answer:(-4,6)

Step-by-step explanation:

you go down four then over six and you find the letter F

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Serjik [45]

Answer:

A) y-1=3(x-2)

Step-by-step explanation:

Point-slope formula.

y-y_1=m(x-x_1)

Given.

Slope (m) = 3

Points (x, y) = (2, 1)

8 0
4 years ago
A line has a slope of \large \frac{5}{3}. Which of the following points could this line pass through?
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Step-by-step explanation:

6 0
3 years ago
Geometry help please!
Gekata [30.6K]

given the following sets.

A = {0, 1, 2, 3}
B = {a, b, c, d}
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3 0
3 years ago
Which of these limits evaluate to 0?
Vikentia [17]
<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\

----------

Part II

\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\

----------

Part III

\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\

7 0
3 years ago
HELLPPPPPPPP A Blue Ray Player costs $150 and each disc costs $15.50.
Sliva [168]

Answer:

150 + 15.50 x 0.075

Step-by-step explanation:

4 0
3 years ago
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