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3 years ago

Two word problems :)

Mathematics

2 answers:

slava [35]3 years ago

8 0

7 out of 50 people so to find the whole amount you must multiply 50 into 8 to get 400 and multiply 7 into 8 to get 56.. Therefore, 56 out of 400 have travelled to a foreign country. It is said 56 or more he would be correct but because he says more then 56 is incorrect
I hope it helps if you think this is incorrect please comment I’ll get my sister to do this for you...

natita [175]3 years ago

6 0

Answer:

Step-by-step explanation:

1.43

2.98

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Step-by-step explanation:

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I need to know number 35 I don’t know how to do this promblem

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3 years ago

In a study of the accuracy of fast food drive-through orders, one restaurant had 40 orders that were not accurate among 307 ord

klemol [59]

Answer:

We conclude that the rate of inaccurate orders is greater than 10%.

Step-by-step explanation:

We are given that in a study of the accuracy of fast food drive-through orders, one restaurant had 40 orders that were not accurate among 307 orders observed.

Let p = population proportion rate of inaccurate orders

So, Null Hypothesis, $H_0$ : p $\leq$ 10% {means that the rate of inaccurate orders is less than or equal to 10%}

Alternate Hypothesis, $H_A$ : p > 10% {means that the rate of inaccurate orders is greater than 10%}

The test statistics that will be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of inaccurate orders = $\frac{40}{307}$ = 0.13

n = sample of orders = 307

So, the test statistics = $\frac{0.13-0.10}{\sqrt{\frac{0.10(1-0.10)}{307} } }$

= 1.75

The value of z-test statistics is 1.75.

Also, the P-value of the test statistics is given by;

P-value = P(Z > 1.75) = 1 - P(Z $\leq$ 1.75)

= 1 - 0.95994 = 0.04006

Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 1.75 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the rate of inaccurate orders is greater than 10%.

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3 years ago