Answer:
- a) 16.4 m, 101°
- b) 6.22 m, 51 m²
Step-by-step explanation:
<u>Find the measure of angle Q:</u>
- 50° + (180° - 130°) = 100°
a) <u>Find PR using the law of cosines:</u>
- PR = √(8² + 13² - 28*13*cos 100°) = 16.4 m (rounded)
<u>Find ∠P using law of sines:</u>
- 16.4/sin 100° = 13/ sin P
- m∠P = arcsin (13 sin 100° / 16.4) = 51° (rounded)
<u>The bearing of R from P is:</u>
b)
<u>Find the measure of h, the distance from Q to PR:</u>
- h/ PQ = sin P
- h = PQ sin P
- h = 8 sin 51° = 6.22 m
<u>Find the area of ΔPQR:</u>
- A = 1/2PR*h
- A = 1/2(16.4)(6.22) = 51 m²
B^2-4ac>0
if this is true then there are 2 Real solutions
b^2-4ac=0
One Real Solution
b^2-4ac<0
Imaginary Solutions
Answer:
For the 6 rows of 4 blocks the answer is 24, for the 4 rows of 4 blocks the answer is 16. Then you do 24x16.
Step-by-step explanation:
6 rows of 4 blocks = 6x4=24
4 rows of 4 blocks= 4x4=16
24
x16
___
124
+ 240
_____
364
So, your answer would be 346 cu in.!! Sorry if I'm wrong!! :(
Answer:
If you need what x equals its -16