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ss7ja [257]
3 years ago
15

The prime factorization of 22750 and 3850

Mathematics
1 answer:
uysha [10]3 years ago
6 0
22750 - 2 × 5^3 × 7 × 13
3850 - 2 × 5^2 × 7 × 11
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Find the height of a triangle with an area of 42 square inches and base of 7 inches. Use the formula for the area of a triangle
disa [49]
A= 1/2bh

fill in formula with known numbers

42= 1/2(7)h
multiply numerators on right side

42= (1*7)/2h

42= 7/2h
divide both sides by 7/2

42 ÷ 7/2= h
to divide fractions, multiply by reciprocal/inverse of 7/2

42 * 2/7= h
multiply numerators

(42 * 2)/7= h

84/7= h

12 inches= h


ANSWER: The height is 12 inches.

Hope this helps! :)
7 0
4 years ago
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Solve using standard algorithm 2.40+1.8 = 36.25+8.67
noname [10]
No solution


Ex:


Simply 2.40+1.8 to 4.2


4 0
3 years ago
What is the longest side of a right angled triangle called?
Anarel [89]

Answer:

The hypotenuse

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3 years ago
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A 17 foot piece of string is cut into two pieces so that the longer piece is 5 feet longer than twice the shorter piece. If the
Vsevolod [243]

Answer:

Shorter piece= 4 ft, longer piece= 13 ft

Step-by-step explanation:

If shorter piece is x

Longer pc is 2x + 5

Together they make 17 feet

So x + 2x + 5 = 17

3 x + 5 = 17

3x = 17 - 5 = 12

3x = 12

X = 12/ 3 = 4

So shorter pc is 4 feet

Longer pc is 2 x + 5

= (2 x 4) + 5

= 8 + 5 = 13

7 0
3 years ago
Coffee: A popular chain of cafes has been receiving online complaints about one store location. Regular customers complained tha
spin [16.1K]

Answer:

z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67  

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=18 represent the ounce cups of coffee that were underfilled

\hat p=\frac{18}{100}=0.18 estimated proportion of ounce cups of coffee that were underfilled

p_o=0.1 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion it's higher than 0.1 or 10%:  

Null hypothesis:p\leq 0.1  

Alternative hypothesis:p > 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed for this case is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a one right tailed test the p value would be:  

p_v =P(Z>2.67)=0.0037  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance thetrue proportion is not significanlty higher than 0.1 or 10% .  

5 0
4 years ago
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