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dmitriy555 [2]
3 years ago
12

Are 12,24,36,48 proportional

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0
No. (limit limit )))) is
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An executive drove home at an average speed of 30 mph to an airport where a helicopter was waiting. The executive boarded the he
wlad13 [49]

Answer:

120 miles

Step-by-step explanation:

Formulate equations.

Distance = rate * time.

D1 = distance from home to airport

D2 = distance from airport to off

D1 + D2 = 150

30 x t1 + 60 x t2 = 150

Divide through by 30

t1 + 2t2 = 5 ----- equation 1

Entire trip took 3 hours

t1 + t2 = 3 -------------------- equation 2

Solve equation 1 and 2 and you get

t1 = 1 hour

t2 = 2 hour

D2 = t2 x speed = 2 x 60

          = 120 miles.

6 0
3 years ago
What is –96 ÷ +3? im a little confused when it comes to math
muminat

Answer:

I think the answer is -32.

Step-by-step explanation:

I'm not sure.

3 0
3 years ago
Read 2 more answers
If cos(u)=4/5 and tan(v)=-12/5 while (3pi/2)
8_murik_8 [283]

Answer:

Step-by-step explanation:

This is an incomplete question

7 0
3 years ago
HELP FAST ILL MAKE BRAINIEST Mr. McClellan compared the weights (in pounds) of pairs of elk antlers dropped at Mount St Helens N
Anika [276]
a.1 Line plot for <span>eight of elk antler pairs at Mount St Helens NVM

</span>The diagram is shown in figure 1.

a.2 Weight of elk antler pairs at Rocky Mountain NP

The diagram is shown in figure 2.

b. Calculate the following for each set of data:

We can found the mean (µ) of a set of data points by adding them up and dividing by the number of data points.

b.1 Purple Mean:

Set: \{34, 34, 30, 30, 30, 28, 28, 26\} \rightarrow  \frac{34+34+30+30+30+28+28+26}{8} \rightarrow \boxed{\mu=30}

b2. Red 
Mean:

Set: \{40, 38, 36, 36, 36, 36, 34, 32\} \rightarrow \frac{40+38+36+36+36+36+34+32}{8} \rightarrow \boxed{\mu=36}

b.3 
<span>Red Median
</span>
The Median is the middle of a sorted list of numbers. <span>The median of a finite list of numbers can be found by arranging all the numbers from smallest to greatest. So, arranging the red set we have:
</span><span>
\{32, 34, 36, 36, 36, 36, 38, 40\}

Given that the number of elements is pair, the median can be solved as follows:

</span>\overline{x}=\frac{x_{(n/2)}+ x_{((n/2)+1)}}{2}

∴ n=8
∴ x_{(n/2)}=x_{(4)}=36
∴ x_{((n/2)+1)}=x_{(5)}=36

Then:

\overline{x}=\frac{36+36}{2}=36

b.4 Purple MAD

The Mean Absolute Deviation (MAD) is when you find the distance of each data point from the mean and then find the mean <span>of those distances. So:
</span>
\{34, 34, 30, 30, 30, 28, 28, 26\} has \mu=30
distances=\{4, 4, 0, 0, 0, 2, 2, 4\} \rightarrow \frac{4+4+0+0+0+2+2+4}{8}= \boxed{MAD=2}

b.5 Red MAD

\{40, 38, 36, 36, 36, 36, 34, 32\} has \mu=36
distances=\{4, 2, 0, 0, 0, 0, 2, 4\} \rightarrow \frac{4+2+0+0+0+0+2+4}{8}= \boxed{MAD=1.5}

 c. Calculate the means-to-MAD ratio for the two areas of collection

c.1 Purple set:

The ratio is the<span> relationship between the mean and the MAD indicating how many times the first number contains the second, so:
</span>
\frac{\mu}{MAD}= \frac{30}{2}=\boxed{15}

c.2 Red set:

\frac{\mu}{MAD}= \frac{36}{1.5}=\boxed{24}

d. What inference can be made about the areas in regard to weight of dropped elk antlers? 

MAD tells us how far, on average, all values are from the middle. So, in the example weight of elk antler pairs at Mount St Helens NVM are, on average, 2 away from the middle. On the other hand, weight of elk antler pairs at Rocky Mountain NP are, on average, 1.5 away from the middle. So, we can assure that elk antler pairs at Rocky Mountain NP weighs more than elk antler pairs at Mount St Helens NVM.


3 0
3 years ago
A rectangle with positive are has length represented by the expression 3x^2+5x-8 and width by 2x^2 +6x write an expression in te
Nata [24]

Answer:

c=10x^2+22x-16\\A=6x^4+28x^3+14x^2-48x

Step-by-step explanation:

Given

Length is l=3x^2+5x-8

Width is w=2x^2+6x

Perimeter of the rectangle is the sum of the sides

\Rightarrow c=2(3x^2+5x-8+2x^2+6x)\\\Rightarrow c=2(5x^2+11x-8)\\\Rightarrow c=10x^2+22x-16

Area is given by

\Rightarrow A=(3x^2+5x-8)(2x^2+6x)\\\Rightarrow A=6x^4+18x^3+10x^3+30x^2-16x^2-48x\\\Rightarrow A=6x^4+28x^3+14x^2-48x

8 0
3 years ago
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