9514 1404 393
Answer:
P = 3x +32
Step-by-step explanation:
If we assume the short vertical edge at top center is 10 yards, as it was in two previous problems with this geometry, then we can find the area of the present parking lot as ...
(x-2)(3x) + x(3x -10) +2x(40) = 6x^2 +64x
where the left vertical rectangle is 3x high and x-2 wide; the center area between vertical rectangles is (2x-2)-(x-2) = x wide and (3x-10) high; and the right vertical rectangle is (x-2 +3x)-(2x-2) = 2x wide and 40 high.
As we said, the right vertical rectangle is 2x wide, so the area that has P as one of its dimensions is ...
A = LW = P(2x)
We want this to be the same as the existing area, so ...
2Px = 6x^2 +64x
P = 3x +32 . . . . . divide by 2x
Answer:
<h2>
3.ALGEBRA Find x and the length of each side if RST is an isosceles triangle with RS = TS</h2>
Question is in image.
<h2>
A. x =4, RS = TS = 23, RT =7</h2><h2>
B. x =2, RS = TS = 20, RT = 5</h2><h2>
C. x =3, RS = TS = 29, RT = 8</h2><h2>
D. x = 5, RS = TS = 18 RT = 4</h2>
<h2>
<em>A</em><em>N</em><em>S</em><em>W</em><em>E</em><em>R</em><em>:</em><em> </em><u>C</u><u>.</u><u> </u><u>x</u><u> </u><u>=</u><u>3</u><u>,</u><u> </u><u>R</u><u>S</u><u> </u><u>=</u><u> </u><u>T</u><u>S</u><u> </u><u>=</u><u> </u><u>2</u><u>9</u><u>,</u><u>R</u><u>T</u><u> </u><u>=</u><u> </u><u>8</u></h2><h2>
Step-by-step explanation:</h2><h2>HOPE ITS HELP</h2>
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<h2>
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Answer:
The Answer is: 6 inches by 5 inches.
Step-by-step explanation:
Given: A structure that is 30 ft by 25 ft.
Scale: 3 in to 15 ft.
Or - Scale: 1 in to 5 ft.
Divide the sides by 5 to get how many 1" sections:
30 ft / 5 = 6 inches
25 ft / 5 = 5 inches
The sides of the drawing are 6 inches by 5 inches. This represents the 30 ft by 25 ft rectangle.
Hope this helps! Have an Awesome Day!! :-)
Answer:
10
Step-by-step explanation: