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Vlad [161]
2 years ago
11

Which quadratic equation has roots - 2 and 1/5 :

Mathematics
1 answer:
Sladkaya [172]2 years ago
7 0

Answer:

5 {x}^{2}  \:  +  \: 8x \:  - 2 \:  =  \: 0

Step-by-step explanation:

sum \: of roots =  - 2 +  \frac{1}{5}  = - \frac{8}{5}  \\ product \: of \: roots =  - 2 \times  \frac{1}{5}  =  -  \frac{2}{5}  \\ from \: general \: equation \\ a {x}^{2}  + bx + c = 0 \\  {x}^{2}  +  \frac{8}{5} x  \: -   \frac{2}{5}  = 0 \\ 5 {x}^{2}   \:  +  \: 8x \:  - 2 \:  =  \: 0

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I need help on this question plz
baherus [9]

Hello!

First of all, for our first scenario, the variation or spread of a data set is represented by the range. You subtract the largest and smallest number in the data set to find how much is in between.

Next, the mode is the number of piece of data that shows up the most in the data set, or the most common piece. Therefore, the most popular color is the mode.

As you can see, number 3 clearly says mean in the problem. This is the average cost.

The median is the middle number. Basically, it splits the data in half. If half of the students are 15 or higher, the middle age is 15, therefore, the median is 15.

Therefore, our answers are below.

2. Mode

3. Mean

1. Range

4. Median

I hope this helps!

7 0
3 years ago
A stray dog ate 40 of your muffins. That was 5/6 of all them! How many are left?
lilavasa [31]
I think that there are 33 left.

I hope this helps you!
3 0
3 years ago
Read 2 more answers
Donna de paul is raising money for the homeless. She discovers that each church group requires 2 hours of let her writing and 1
Salsk061 [2.6K]

Answer:

x  =  7

y  =  3

z (max)  =  4950/3  =  1650

Step-by-step explanation:

Let call  

x numbers of church goup and

y numbers of Union Local

Then  

First contraint

2*x + 2*y ≤ 20

Second one

1*x + 3*y ≤ 16

Objective Function

z = 150*x + 200*y

Then the system is

z = 150*x + 200*y To maximize

Subject to:

2*x + 2*y ≤ 20

1*x + 3*y ≤ 16

x ≥ 0 y ≥ 0

We will solve by using the Simplex method

z - 150 *x - 200*y = 0

2*x + 2*y + s₁ = 20  

1*x + 3*y + 0s₁ + s₂ = 16

First Table

z           x          y          s₁           s₂          Cte

1        -150    -200       0            0     =      0

0          2         2           1            0     =    20

0          1          3          0            1      =     16

First iteration:

Column pivot   ( y column ) row pivot (third row) pivot 3

Second table

z           x                y          s₁           s₂                Cte

1       -250/3           0          0         200/3    =    3200/3

0      - 4/3               0          -1           2/3       =    -20/3

0         1/3               1            0           1/3       =    -20/3

Second iteration:

Column pivot  ( x column ) row pivot  (second row)  pivot  -4/3

Third table

z           x                y          s₁           s₂                Cte

1            0               0      750/12    700/6    =   4950/3

0            1                0        3/4          -1/2     =    7

0            0                1         -1/4          1/2     =  9/3

5 0
3 years ago
The military academy is placing cadets in rows for the parade. All rows must have the same number of cadets. If A company has 64
scoray [572]

Answer:

72

Step-by-step explanation:

If we find the average for both companies, it is 72, therefore there are two rows each with 72 cadets

4 0
2 years ago
Read 2 more answers
M=1.33333(N+20). If N=16,find M<br><br>​
aalyn [17]

Answer:

M=47.99988

Step-by-step explanation:

M=1.33333(16+20)

=1.33333(36)

=47.99988

8 0
3 years ago
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