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1 answer:
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Answer: They are parallel
Step-by-step explanation:
If two lines are parallel , then they must have the same slope and if two lines are perpendicular , the product of their slope must be -1.
To check this , we must calculate the slope of the two lines given.
Slope =
from the first point
= 2
= 1
= 5
= -1
substituting the values
slope 1 = 1 - 2 / -3 - 5
slope1 = -1 / -8
slope 1 = 1/8
Using the same format to calculate the slope of the second line
= -2
= 0
= -1
= 15
slope 2 = 0 - (-2) / 15 - (-1)
slope 2 = 2/16
slope 2 = 1/8
Since slope 1 = slope 2 , this implies that the lines are parallel
Answer:
nth term =
Step-by-step explanation:
Let us assume that the given sequence is a G.P.
Now, if the first term of the G.P. is a and the common ratio is r, then
Third term = .......... (1) and
20th term = ........... (2)
Now, dividing equation (2) with equation (1) we get
⇒
⇒ r = 1.2.
Hence, from equation (1) we get
a(1.2)² = 11
⇒ a = 7.639 (Approx.)
Therefore, the general term of the sequence i.e. nth term = (Answer)
2 ways: make a little divide tree based on how many times you can divide it. Like you have sqrt88 you know it can divide by 2. So its 2 and 44, and 44 can be broken to 2 and 22, then 2 and 11. 11 can’t be divided anymore.
Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.
Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.
Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.
Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.