Answer:
Part A) Barbaroid will be executed
Part B) 75 more globin soldiers
Step-by-step explanation:
The army sizes of ORC leaders are
normally distributed with a mean of 5600 goblin soldiers and a standard deviation of 750 goblin soldiers.
The rule is that, if an Orc Leader shows up with an army of a z-score lower than
-1.5, he is immediately executed.
We want to determine whether Lord Barbaroid, an Orc Leader, who appears with an army of 4400 goblin soldiers,
based on the Orc Rule, will he be executed or not.
We find the z-score corresponding to 4400 using
We substitute x=4400 , the standard deviation and the mean to get:
Since Lord Barbaroid's z-score , -1.6 is less than -1.5 he will be executed.
Part B)
We want to find how many more goblin soldiers Lord Barbaroid have needed in order to NOT be executed and meet that Z-Score.
So we need to find the number of globin soldiers that corresponds to -1.5.
Therefore Barbaroid needed 4475-4400=75 more globin soldiers.
The perimeter of a triangle assuming that all the sides are the same, would be 3 multiplied by 28 to get 84. Since the perimeter of the square is the same, that would mean that 84 units is the total addition of the 4 sides of the square. So divide 84 by 4 to get the length of one side ( which is 24 units).
Finally, the area of a square is defined as two sides multiplied by each other, so 24 multiplied by 24.
Hope this helps.
The answer is d because 2+y is the sum of 2 and y and then you multiply it by 5
Answer:
Largest Median: Same
Largest Range: Castro
Largest IQR: Castro
Step-by-step explanation:
With a box-and-whisker plot, the box represents the upper and lower quartiles, the vertical line inside the box represents the median, and the lines on either side of the box show the high and low of the range.
Largest Median: Medians are the same because the verticle line inside the boxes is at 7 for both
Largest Range: Ms Castro's Class- the lines on either side of the box for Ms Castro go from 1-10 while the other class only goes from 4-10.
Largest IQR (interquartile range) Ms. Castro's class: their IQR goes from 5-8 while the other class only goes from 6-8
p(r + s) = 5 and q(r + s) = 3.
by simply addind those two equations.
p(r + s) + q(r + s) = 5 + 3
(p + q) (r + s) = 8 Statement #2: (p + q) = (r + s)
(p+q)×(r+s)=(p+q)×(p+q)=(p+q
it's been said it's not allowed us to arrive at a specific numerical value. The statementby itself inadequate.
