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A football is kicked into the air and follows the path defined by h=-2x^2+16x, where x is the time in seconds and h is the height in meters. What is the maximum height reached by the football?
Answer:
maximum height=h=32 meters
Step-by-step explanation:
The given equation is the equation of the parabola or quadratic equation.
The maximum height of the ball will occur at the axis of symmetry.
For the axis of symmetry let h=0,
so,
comparing this equation to standard quadratic/parabola's equation, we get
a= -2, b=16 and c=0
Formula for axis of symmetry is x=-b/2a
x=-16/2*(-2)
x=-16/-4
x=4 it means axis of symmetry is vertical line through the point x=+4, so the maximum height will occur at x=+4
put x=4 to get maximum height as;
Maximum height
Answer:
4 times
Step-by-step explanation:
Answer:
P(B) = 8/12
P(R | B) = 4/11
P(B ∩ R) = 8/33
The probability that the first ball chosen is black and the second ball chosen is red is about 24 percent.
Step-by-step explanation:
I just got it right on edge 2020. Good luck with school!!
Answer:
y = {1,2}
Step-by-step explanation:
5y^2 - 4y - 9 = y + 1
5y^2 - 5y - 10 = 0
5(y^2 - y - 2) = 0
5 (y - 2) (y - 1) = 0
y = {1,2}
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