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3 years ago

A is a set of factors of 12. Which one of the following is not member of A? *

Mathematics

2 answers:

vesna_86 [32]3 years ago

6 0

Answer: 5
Explanation:
3x4=12
4x3=12
6x2=12
But 5 does not equal 12

SSSSS [86.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

3*4=12

4*3=12

6*2=12

but 12 is not factor of 5

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Please help me with this

77julia77 [94]

Just have to use cosine rule!!! :)

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3 years ago

Which of the following is equal to -11? 0-6-(-5) 0-5+-6 0-5+6

Julli [10]

The answer is 0-5+-6.

EXPLANATION:

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4 years ago

Read 2 more answers

An animal shelter spends $2.35 per day to care for each cat and $5.50 per day to care for each

lora16 [44]

Equation:
89.50=2.35c+5.50d

If theres 22 dogs and cats in total you can plug in number less than 22 for c(# of cats) and d(# of dogs).

So we try pats numbers 8 cats and 14 dogs so

89.50=2.35(8)+5.50(14)

89.50=18.8+77

89.50=95.8

So pats numbers were wrong so we try different numbers

So i started pluging in numbers from under 22 so i got c is 10 and d is 12 lets try it with the equation

89.50=2.35(10)+5.50(12)

89.50=23.5+66

89.50=89.50 so it works the answer to how many number of dogs and cats is 12 dogs and 10 cats

6 0

3 years ago

Abby, Deborah, Mei-Ling, Sam, and Roberto work in a firm's public relations office. Their employer must choose two of them to at

sattari [20]

Answer:

a) Ω = { {Abby, Deborath}, {Abby, Mei-Ling}, {Abby, Sam}, {Abby,Roberto}, {Deborah, Mei-Ling}, {Deborah, Sam}, {Deborah, Roberto}, {Mei-Ling, Sam}, {Mei-Ling, Roberto}, {Sam, Roberto} }

b) 0.1

c) 0.4

d) 0.3

Step-by-step explanation:

a) The sample space must contain every possible combination of two names. Since we dont care about the order of the chosen names, we can describe every element of the sample space as a subset of 2 elements of the set {Abby, Deborah, Mei-Ling, Sam, Roberto}. That subset will represent the names of the chosen persons. With this in mind, we conclude that the sample space is

Ω = { {Abby, Deborath}, {Abby, Mei-Ling}, {Abby, Sam}, {Abby,Roberto}, {Deborah, Mei-Ling}, {Deborah, Sam}, {Deborah, Roberto}, {Mei-Ling, Sam}, {Mei-Ling, Roberto}, {Sam, Roberto} }

b) The cardinality of the sample space Ω is 10. Since all choices are equally likely, any choice will have probability $\frac{1}{10} = 0.1$ , because the 10 of them combined must add up 1.

c) We need to find all possible choices that includes Mei-Ling, those will be our favourable cases. The amount of favourable cases must be divided to the total amount of cases (the cardinality of Ω) in order to obtain the probability of Mei-Ling being chosen. Mei-Ling is included on 4 choices (one for each of her partners), this means that she has a probability of $\frac{4}{10} = 0.4$ to being chosen.

d) We have 3 favourable cases ,the choices {Abby, Deborah}, {Abby, Mei-Ling} and {Deborah, Mei-Ling}, which neither of them contain a man. By dividing that number to the total number of cases, we obtain a probability of $\frac{3}{10} = 0.3$ that neither of the two men are chosen

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4 years ago

What is the initial value of the exponential function

VARVARA [1.3K]

Answer:

o943

Step-by-step explanation:

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3 years ago