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MA_775_DIABLO [31]
3 years ago
12

The 24 students in Ms.Lee’s class each collected an average of 18 cans for recycling. The 21 students in Mr.Galvez’s class each

collected an average of 25 cans for recycling. How many more cans were collected by Mr. Galvez’s class than Ms.Lee’s class?
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

Answer:

93 cans.

Step-by-step explanation:

21*25=525

24*18=432

525-432=93

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A submarine left Diego Garcia five hours before a cruise ship. The ships traveled in opposite directions. The cruise ship travel
Rina8888 [55]

Answer:

The speed of the submarine is 15.429 miles per hour.

Step-by-step explanation:

Let suppose that both ships travel at constant velocities. As we know that both travel in opposite directions, it is supposed that cruise ship moves in +x direction, whereas submarine in -x direction. Kinematic equations for each sheep are described below:

Ship

x_{Sh} = x_{o} + v_{Sh}\cdot t

Submarine

x_{Su} = x_{o}+v_{Su}\cdot t

Where:

x_{o} - Position of Diego Garcia island, measured in miles.

x_{Sh}, x_{Su} - Current positions of ship and submarine, measured in miles.

v_{Sh}, v_{Su} - Velocities of ship and submarine, measured in miles per hour.

t - TIme, measured in hours.

If we know that x_{Sh} - x_{Su} = 241\,mi, v_{Sh} = 19\,\frac{mi}{h} and t = 7\,h, then:

x_{Sh} - x_{Su} = (v_{Sh}-v_{Su})\cdot t

We clear now the velocity of submarine:

\frac{x_{Sh}-x_{Su}}{t} = v_{Sh}-v_{Su}

v_{Su} = v_{Sh}-\frac{x_{Sh}-x_{Su}}{t}

v_{Su} = 19\,\frac{mi}{h} -\frac{241\,mi}{7\,h}

v_{Su} = -15.429\,\frac{mi}{h}

Speed of the submarine is the magnitude of its velocity, which is 15.429 miles per hour.

4 0
3 years ago
Please help quickly it is super late rn
pychu [463]

Step-by-step explanation:

-4^(-5)/ 2^(-3) =

2³/(-4)^5 =

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7 0
3 years ago
Need some help with these problems please.
goldenfox [79]

Answer:

See below.

Step-by-step explanation:

a.  

Divide the leading terms:

6x^4 / 2x^2 = 3x^2

3x2 is a parabola so the long run is

as x ---> +/- infinity r(x) ----> + infinity. (answer).

b.

10,000x^3 / 50 x^3

= 200.

So r(x) as a horizontal asymptote at y ( r(x)) = 200.  (answer).

3 0
3 years ago
Simplify 28/184 by reducing to lowest form<br> A) 1/46<br> B) 1/7<br> C) 14/92<br> D) 7/46
Elodia [21]
It’ll be D) 7/46 you can reduce it by dividing everything with 4
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3 years ago
PLEASE HELP!! 15 POINTS!!!!
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