Write the equation (3,5) in standard form

Mathematics

1 answer:

iris [78.8K]3 years ago

7 0

Answer:

We can write out 3! (three factorial) as 3x2x1, and we can write out 5! as 5x4x3x2x1. This means that, since 3x2x1 is on the top and the bottom of the fraction, it cancels out. This leaves us with 1 on top, and 4x5=20 on the bottom.

Step-by-step explanation:

can you please help me with my question

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Let f be the following piecewise-defined function. f(x)equals left brace Start 2 By 1 Matrix 1st Row 1st Column x squared plus

Colt1911 [192]

Answer:

the function is continuous but not differentiable in x=3

Step-by-step explanation:

for f(x) defined as

x²+5 for x≤3

3*x+5 for x>3

then for f to be continuous then

when x→a , lim f(x) = f(a)

thus

from the left

when x→3⁻ , lim f(x) = lim x²+5 = 3²+5 = 14

from the right

when x→3⁺ , lim f(x) = lim 3*x+5 = 3*3+5 = 14

and f(3) = 3²+5 = 14

since both limits converge and are equal to f(3), then the function is continuous in 3

Nevertheless, the function is not differentiable in 3 since the curve is not smooth in f(3) ( it has an sharp change in f(3) ) , then the function is not differentiable in x=3

to prove it , when x=3 and

when h→0⁻ , f'(x=3)= lim [f(x+h)-f(x)] /h = lim [(x+h)²+5 - (x² + 5)]/h = lim [2*x*h+h²] /h = lim [2*x+h] = 2*3+0 = 6

when h→0⁺ , f'(x=3)= lim [f(x+h)-f(x)] /h = lim [3*(x+h)+5 - (3*x + 5)]/h = lim [3*h] /h = lim 3 = 3

since the limits do not converge →the limit does not exist → the derivative does not exist → the function is not differentiable in x=3

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4 years ago

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Shtirlitz [24]

Answer:

Pi^3 * x^4

Step-by-step explanation:

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