Wide is 5 x 5 = 25 feet;
P = 2 x width + 2 x wide = 10 + 50 = 60 feet;
Answer:
Therefore, height of the wall at which the ladder is placed is AB = 39.12 foot.
Step-by-step explanation:
Let,
AB = height of the wall at which the ladder is placed
AC = height of the ladder = 40 foot
BC = distance from the wall to the base of the ladder = 8 feet
To Find:
AB = height of the wall at which the ladder is placed = ?
Solution:
Consider a right angled triangle Δ ABC right angle at angle B,
So by Pythagoras theorem we have
![(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}](https://tex.z-dn.net/?f=%28%5Ctextrm%7BHypotenuse%7D%29%5E%7B2%7D%20%3D%20%28%5Ctextrm%7BShorter%20leg%7D%29%5E%7B2%7D%2B%28%5Ctextrm%7BLonger%20leg%7D%29%5E%7B2%7D)
AC² = AB² + BC²
Substituting the given values in above equation we get
40² = AB² + 8²
∴ AB² = 40² - 8²
∴ AB² = 1536
![\therefore AB =\pm\sqrt{1536} \\\\(distance\cannot\ be\ negative)\\\therefore AB =39.19\ foot\\](https://tex.z-dn.net/?f=%5Ctherefore%20AB%20%3D%5Cpm%5Csqrt%7B1536%7D%20%5C%5C%5C%5C%28distance%5Ccannot%5C%20be%5C%20negative%29%5C%5C%5Ctherefore%20AB%20%3D39.19%5C%20foot%5C%5C)
Therefore, height of the wall at which the ladder is placed is AB = 39.12 foot.
Answer:
Part A: y = 4.5x + 22
Part B: 31 inches
Step-by-step explanation:
Part A:
the y-intercept appear to be at 22
the slope can be found by using the points (0, 22) and (4, 39)
m = <u>39 - 22</u>
4 - 0
m = 17 / 4 = 4.3 and this is close to 4.5
Part B:
plug in 2 for 'x' in the equation: y = 4.5x + 22
y = 4.5(2) + 22
y = 9 + 22
y = 31
Answer:
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