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pickupchik [31]
3 years ago
12

What will be the linear equation for the shown table?​

Mathematics
1 answer:
vladimir1956 [14]3 years ago
3 0

Answer:

y=2x+5

Step-by-step explanation:

To find a linear equation you must find the slope and y intercept to create an equation in y=mx+b form (slope-intercept form)

So slope is = y2-y1 / x2-x1 [2 and 1 are subscripts] so 11-7/3-1 so m=4/2 = 2

Slope = 2, now find b

So using y = mx + b, substitute what you know so 7 = 2(1) + b so b=7-2 = 5

Put it all together y = 2x + 5

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A sign next to a roller coaster at an amusement park says, “You must be at least 60 inches tall to ride.” Noah is happy to know
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x>60 or x=60

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you are going to borrow $71500.00 for 200 days you are to be loaned the money at an interest rate of 7.5% and you are given the
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Answer:

given,

Amount borrowed = $71500

Time = 200 days

interest rate = 7.5 %

ordinary interest rate for year = 71500\times \dfrac{7.5}{100}

                                                  = $5362.5

exact interest rate for the year = 71500\times \dfrac{7.5}{100}\times \dfrac{200}{365}

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7 0
3 years ago
Total blood cholesterol level was measured for each of
laiz [17]
<h3>Answer: Mean = 218.9.</h3><h3>Median = 229</h3><h3>Mode = Zero mode.</h3>

Step-by-step explanation:

Given blood cholesterol level was measured for each of 8 adults (in mg/dL) are:

264, 191, 160, 148, 262, 212, 268, 246

In order to find the mean, we need to add all those 8 numbers and divide by 8.

Therefore, mean = \frac{264+191+160+148+262+212+268+246}{8} =\frac{1751}{8} =218.9.

<h3>Mean = 218.9.</h3>

In order to find the median, we need to arrange them in ascending order:

148, 160, 191, 212, 246, 262, 264, 268.

The middle most two values are 212 and  246.

Therefore, median = \frac{212+246}{2} =\frac{458}{2} = 229.

<h3>Median = 229.</h3>

\mathrm{The\:mode\:is\:the\:term\:in\:the\:data\:set\:that\:appears\:the\:most.}

\mathrm{If\:there\:is\:more\:than\:one\:term\:that\:appears\:the\:most,\:then\:there\:is\:no\:mode.}

\mathrm{Count\:the\:number\:of\:times\:each\:element\:appears\:in\:the\:list}

\begin{pmatrix}148&160&191&212&246&262&264&268\\ 1&1&1&1&1&1&1&1\end{pmatrix}

\mathrm{The\:most\:common\:element\:is\:not\:unique,\:so\:there\:is\:no\:mode}

<h3>Therefore, Mode = Zero mode.</h3>
5 0
4 years ago
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